Patching a file without temporary diff file

Question

I am trying to revert a file from a previous version of the same file, using diff and patch

diff_out=$(diff -u $name $chVer/$name.latest) patch -u $name $diff_out

Where $name is the file name i want to revert, $chVer is the folder of all the older versions of the file

Unfortunately this doesn't work

patch: unrecognized option '---' patch: Try 'patch --help' for more information.

the $diff_out content is not read by the patch command as a file, thus do i need the output the content of the diff to a temporary file that i read with patch ? I wanted not to do that, because i will delete that file as soon as the patch is done

Quote your parameter expansions, and see if you still have a problem. — chepner
– chepner, Commented Mar 2, 2018 at 14:24

Daniel Harms · Accepted Answer · 2018-03-02 13:48:25Z

1

Try $diff_out | patch -u $name

patch will accept a diff from stdin if not provided as an argument.

answered Mar 2, 2018 at 13:48

Daniel Harms

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Daniel Harms Over a year ago

This answers the question of "how to patch a file with a temporary diff file". If the answer should be improved or is incorrect, please comment.

Thomas · Accepted Answer · 2018-03-02 20:40:42Z

You can avoid the temporary file by using process substitution:

patch -u $name <(diff -u $name $chVer/$name.latest)

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