Parsing options that take arguments in getopts

Question

I have the following program foo, that can take one of three optional flags, f, g, or s:

usage() { echo "Use this correctly" } while getopts "fgs" opt; do case $opt in f) echo f foo="$OPTARG" echo $foo ;; g) echo g foo="g" ;; s) echo s foo="s" ;; esac done if [ -z "$foo" ] then usage exit fi echo $foo exit

When I do foo -g or foo -s I get the expected outputs:

g g

and

s s

respectively. But when I do foo -f bar I expect

f bar bar

but get

f Use this correctly

indicating that $foo is not being set properly in the -f case. What am I doing wrong?

hnicke · Accepted Answer · 2018-07-11 15:00:26Z

You have to replace

while getopts "fgs" opt; do

with

while getopts "f:gs" opt; do

Options that take an argument must be followed by a colon. Only for these options, getopts sets the OPTARG variable.

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