Extract exact URL's from string in php

The problem is in you are matching a link with a boundary of the http word

$regex = '#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#'; // ^^ note this 

omitting the boundary will get the full list of urls in your string

$regex = '#https?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#'; 

will output:

Array ( [0] => http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgend [1] => http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpgand ) 

You SHOULD match against some fixed suffix in the end of the url.

I will assume that you want to match against jpg,jpeg,png images , so your pattern may look like:

$regex = '#https?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/)\.(jpg|jpeg|png))#'; 

Live example: https://3v4l.org/WACo1

You can make a for loop. With the size of the array $matches And then print the result.

<?php $string = "hi new image one http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpgand two are http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpgend"; $regex = '#\bhttps?://[^,\s()<>]+(?:\([\w\d]+\)|([^,[:punct:]\s]|/))#'; preg_match_all($regex, $string, $matches); echo "<pre>"; for($i=0;$i<sizeof($matches);$i++){ print_r($matches[$i]); } 

Try this, and let me know if it match your needs

Here is the answer to your question

 $string = "hi new image one http://xxx/images/c4ca4238a0b923820dcc509a6f75849b208754572.jpg and two are http://yyy/images/c1f1a611c1147c4054c399c01f8bad76686484492.jpg end"; $strArray = explode(' ', $string); $newString = ""; $url = array(); foreach($strArray as $word) { if (substr($word, 0, 7) == "http://" || substr($word, 0, 8) == "https://") { $url[] = $word; } else { if ($newString != '') $newString .= ' '; $newString .= $word; } } print_r($url);