Is that possible in PHP to pass variables into a function when they are not set as parameters? [duplicate]

Question

is that possible in PHP to pass variables into a function when they are not set as parameters? I mean something like the following:

$pdo=PDOconnection; $arr=someArray; function myFunction(){ if(no-parameters){ $input=$pdo; //or $input=$arr; } }

yes this is possible. just make sure those 2 lines are before the call of myFunction(). — GeneCode
– GeneCode, Commented Mar 26, 2019 at 1:13

Greg Schmidt · Accepted Answer · 2019-03-26 03:14:05Z

0

@Nick's answer should work. This might be a little simpler?

$pdo=PDOconnection; function myFunction($input = null){ if($input === null){ $input=$GLOBALS['pdo']; } }

answered Mar 26, 2019 at 3:14

Greg Schmidt

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2 Comments

Nick Over a year ago

The only issue with this is that it prevents passing null as a value.

Greg Schmidt Over a year ago

There's always going to be some value that makes no sense whatsoever to pass in, whether null, false, true, 0, "nope" or whatever. null seemed to fit the example given.

Nick · Accepted Answer · 2019-03-26 00:46:49Z

You could use func_num_args to check for the number of function arguments, and if the result is 0, get the value from the $GLOBALS array e.g.

$foo = 4; function myFunction () { if (!func_num_args()) { $input = $GLOBALS['foo']; } else { $input = func_get_arg(0); } echo "$input\n"; } myFunction('hello'); myFunction();

Output:

hello 4

Demo on 3v4l.org

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