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I am new to batch file coding and am trying to write a simple If-Else statement.

I have tried to use delayedexpansion as suggested in other questions but still don't seem to get the right value

@echo off setlocal ENABLEDELAYEDEXPANSION SET VAR=portrait IF %VAR% == portrait do ( SET /a height=1920; set /a width=1080; ) else do( set /a height=1080; set /a width=1920; ) echo %height%

The code above gives the output as 1080, while I am expecting 1920 based on the logic I wrote. Can someone please help me understand?

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    Your example is not working. If you'll fix all syntactic errors it will work as expected. Commented May 30, 2019 at 7:14
  • I didn’t get any syntax error when I ran this. I do get an output. Are you getting an error? Commented May 30, 2019 at 7:15
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    Have you tried this exact example? Mind do and semi-colons. Commented May 30, 2019 at 7:18

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You issue is mainly because there's no such thing as an If / Do or Else / Do statement. Also you should try to remember that Set /A is really for arithmetic, and you're not doing math, just setting values to names.

If "%VAR%" == "portrait" ( Set "height=1920" Set "width=1080" ) Else ( Set "height=1080" Set "width=1920" ) Echo %height%

However, you can in this case, still use Set /A to shorten your commands a little; because Set /A allows for multiple names to integer values within the same statement.

If "%VAR%" == "portrait" ( Set /A height=1920, width=1080 ) Else ( Set /A height=1080, width=1920 ) Echo %height%
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