Is it possible to assign a function to function pointer dynamically?

Question

Is it possible to somehow declare and assign a function to function pointer func in main() without having an actual function add()?

Current Code:

#include <iostream> int add(int a, int b) { return a + b; } int main() { typedef int (*funcPtr)(int a, int b); funcPtr func = &add; std::cout << func(2,3) << std::endl; }

Preferred Style: (if possible)

#include <iostream> int main() { typedef int (*funcPtr)(int a, int b); funcPtr func = (funcPtr){return a + b}; // is something like this possible? std::cout << func(2,3) << std::endl; }

Is there a way to assign a function to function pointer dynamically like my last code?

@stark Oh, I don't know what what you mean then. I'm trying to assign a function to a function pointer like I wrote. — Zack Lee
– Zack Lee, Commented Jul 13, 2019 at 15:28
Sounds like what you want is closer to const auto func = [](const auto a, const auto b){ return a + b; }; — Jesper Juhl
– Jesper Juhl, Commented Jul 13, 2019 at 15:31

songyuanyao · Accepted Answer · 2019-07-13 15:28:49Z

5

You can use lambda; which could convert to function pointer implicitly if capture nothing.

funcPtr func = [](int a, int b) {return a + b;};

LIVE

edited Jul 13, 2019 at 15:28

answered Jul 13, 2019 at 15:23

songyuanyao

174k16 gold badges327 silver badges432 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Is it possible to assign a function to function pointer dynamically?

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related