Currying Functions in Scala

Question

I am new to Scala and I just started learning it and now trying some exercises. This one in particular I have a trouble understanding.

I understand up to the (f: (A, B) => C) part, but the rest I dont quite get it. Can someone please explain what's happening after the anonymous function part?

Thanks!

This is the function:

def curry[A, B, C](f: (A, B) => C): A => (B => C) = a => b => f(a, b)

follow this codecommit.com/blog/scala/function-currying-in-scala it will help you to understand currying — rohit prakash
– rohit prakash, Commented Jul 18, 2019 at 7:34
@rohitprakash yeah i've read this, gave me a bit of an idea thanks — greenmonkeys
– greenmonkeys, Commented Jul 18, 2019 at 7:48

jwvh · Accepted Answer · 2019-07-19 06:02:21Z

def curry a method named "curry"
[A, B, C] will deal with 3 different types
(f it will receive an argument that we'll name "f"
: (A, B) => C) that argument is type "function that takes A,B and returns C"
: A => (B => C) "curry" returns type "function that takes A and returns function that takes B and returns C"
= here's the "curry" code
a => b => f(a, b) function that takes an argument (we'll call "a") and returns a function that takes an argument (we'll call "b") that returns the value returned after "a" and "b" are passed to "f()"

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