How to resolve name conflict between class name and function name

Question

Is there any (good) way of having equally named class and global function in the same namespace in C++?

Below code does not compile because it favors function over class name.

void PrintNumber( int val ) { std::cout << "from function: " << val << std::endl; } struct PrintNumber { void operator()( int val ) const { std::cout << "from operator: " << val << std::endl; } }; int main() { auto f1 = std::function<void(int)>( PrintNumber() ) ; // Functor class instance // ERROR occurs here auto f2 = std::function<void(int)>( PrintNumber ) ; // Global function f1( 123 ); f2( 456 ); cin.get(); }

Not an answer to the question, but the obvious solution would be to rename the class to NumberPrinter or similar. PrintNumber isn't a good class name. — Ted Lyngmo
– Ted Lyngmo, Commented Mar 8, 2020 at 10:28
Rename class/structure like CNumberPrinter to StructNumberPrinter — Build Succeeded
– Build Succeeded, Commented Mar 8, 2020 at 10:34

kabanus · Accepted Answer · 2020-03-08 10:49:26Z

Use the full name struct PrintNumber. This can't be done directly in your initialization of std::function:

#include<iostream> #include<functional> struct PrintNumber { void operator()( int val ) const { std::cout << "from operator: " << val << std::endl; } }; void PrintNumber( int val ) { std::cout << "from function: " << val << std::endl; } int main() { struct PrintNumber p; auto f1 = std::function<void(int)>( p ) ; // Functor class instance occurs here auto f2 = std::function<void(int)>( PrintNumber ) ; // Global function f1( 123 ); f2( 456 ); std::cin.get(); }

though probably best to change names or namespaces to avoid ambiguity.

Collectives™ on Stack Overflow

How to resolve name conflict between class name and function name

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related