Length of a string using conditionals (using Python) [duplicate]

Question

I was trying a code where upon entering a string, we get the length of the string. However, if we enter an integer or float data type we get the "Wrong data type" message. Please find my code below:

def string_length(word): if type(word) == int: return "This is wrong data type" elif type(word) == float: return "Wrong data type again!" else: return len(word) word = input("Enter the string: ") print(string_length(word))

The program is running fine for string input, however, for integers it is returning the number of digits ("characters") instead of the message. Please find below the output terminal window:

PS D:\Python\Practice> python .\stringlength_exercise2.py Enter the string: Hellooo 7 PS D:\Python\Practice> python .\stringlength_exercise2.py Enter the string: Hello there 11 PS D:\Python\Practice> python .\stringlength_exercise2.py Enter the string: 123 3 PS D:\Python\Practice> python .\stringlength_exercise2.py Enter the string: 12.20 5

Can you please help me identify / rectify the mistake?

Thanks in advance.

As @AlexanderLekontsev wrote, your value is always a string. Now, the question is what exactly are you trying to do? Are you just trying to learn about Python, or is there some goal you are trying to accomplish? — zvone
– zvone, Commented Jul 22, 2020 at 10:54
@zvone hi, yes i am trying to learn about Python. I was trying out few conditional statements to try to calculate the length of string. If the input is string data type, then it should return the number of characters in that string. Otherwise, if the entered data type is int/float, it should return the message in if/elif conditional. — Varun R
– Varun R, Commented Jul 22, 2020 at 11:02

quamrana · Accepted Answer · 2020-07-22 10:57:49Z

Did you mean to have a function which tries these types for you?

def tryTypes(word): try: print(string_length(int(word))) return except ValueError as e: pass try: print(string_length(float(word))) return except ValueError as e: pass print(string_length(word)) word = input("Enter the string: ") tryTypes(word)

Sai · Accepted Answer · 2020-07-22 11:19:52Z

As your input can be int and float you can use:

def string_length(input_string): if input_string.isdigit(): return "Integer" elif input_string.startswith("-") and input_string.count('-') == 1: str_ = input_string.replace('-','') if input_string.replace('-','').isdigit(): return "Integer" elif input_string.count('.') == 1 and str_.replace('.','').isdigit(): return "Float" elif input_string.count('.') == 1 and input_string.replace('.','').isdigit(): return "Float" else: return len(word)

But then again, '-1'.isdigit() returns False. There is actually no correct answer, because it is not clear what exactly OP is trying to do.
@SaiSreenivas thanks for the blueprint. It returns the datatype output. However, it also returns a None. Enter the string: 12 Integer None. Can you please let me know if there is any error?

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