categories = {'player_name': None, 'player_id': None, 'season': None} L = ['Player 1', 'player_1', '2020'] How can I iterate over list and assign its values to the corresponding keys? so it would become something like:
{'player_name': 'Player 1', 'player_id': 'player_1, 'season': '2020'} thanks
If python >= 3.6, then use zip() + dict(), if < 3.6, looks dict is un-ordered, so I don't know.
test.py:
categories = {'player_name': None, 'player_id': None, 'season': None} L = ['Player 1', 'player_1', '2020'] print(dict(zip(categories, L))) Results:
$ python3 test.py {'player_name': 'Player 1', 'player_id': 'player_1', 'season': '2020'} If the list has items in the same order as dictionary has keys i-e if player_name is the first element in the list then 'player_name' in the dictionary should come at first place
categories = {'player_name': None, 'player_id': None, 'season': None} L = ['Player 1', 'player_1', '2020'] for key, value in zip(categories.keys(), L): categories[key] = value You could try something like this
categories = {'name':None, 'id':None, 'season':None} L = ['Player 1', 'player_1', '2020'] it = iter(L) for x in it: categories['name'] = x categories['id'] = next(it) categories['season'] = next(it) 
cat = { 'player_name' : None, 'player_id ': None, 'season' : None } L = ['Player 1', 'player_1', 2020] j = 0 for i in cat.keys(): cat[i] = L[j] j += 1 This should solve your problem
