How do I incorporate one function into another?

Question

I have to define two separate functions z(x, mu, c) and landau(x, A, mu, c). z = (x-mu)/c and landau = 1.64872*A*np.exp(-0.5(z+np.exp(-z)))

As they share variables I have tried to define z inside the definition of landau as a function itself and not as a function. Also, I have tried to define z as a function outside the definition of landau. However, nothing I try seems to work. Either python tells me "'float' object is not callable" or "bad operant type for unary -: 'function'". Is there a quick fix for this?

landau(1,1,1,1) should give an answer that's roughly equal to 1

def landau(x, A, mu, c): # Functie Landau met variabelen x, A, c en mu # A = amplitude # c = schaalparameter # mu = positieparameter def z(x, mu, c): return (x-mu)/c return 1.64872*A*np.exp(-0.5(z(x, mu, c)+np.exp(-z(x, mu, c))))

I suggest you start with defining two separate functions. Try to call them and see what happens. You can update this question with your entire code, plus full error tracebacks. — quamrana
– quamrana, Commented Jan 18, 2021 at 14:14
Took a quick look and you're missing an operator between -0.5 and the open parenthesis in -0.5(z... — user5386938
– user5386938, Commented Jan 18, 2021 at 14:15

TheEagle · Accepted Answer · 2021-01-18 14:40:09Z

You missed a * in -0.5 * (z(x. At least I'm assuming it's supposed to be a multiplication.

import numpy as np def landau(x, A, mu, c): # Functie Landau met variabelen x, A, c en mu # A = amplitude # c = schaalparameter # mu = positieparameter return 1.64872 * A * np.exp(-0.5 * (z(x, mu, c) + np.exp(-z(x, mu, c)))) def z(x, mu, c): return (x - mu) / c landau(1, 1, 1, 1) 0.9999992292814129

btw, nothing wrong with having z defined in landau like you did. not sure if one way or the other is the preferred style.

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