Suppose I have a Flag enum like this:
From enum import Flag class suspicion(Flag): TOT_PCNT_LOW = 1 IND_PCNT_LOW = 2 IND_SCORE_LOW = 4 And suppose I have an integer that was constructed using these flags
i = suspicion.IND_PCNT_LOW.value | suspicion.TOT_PCNT_LOW.value # i == 3 How do I get a list of the names of the flags that are set in the integer? For example:
print(some_method(i)) # prints ["IND_PCNT_LOW", "TOT_PCNT_LOW"] Setup code:
from enum import Flag class Suspicion(Flag): TOT_PCNT_LOW = 1 IND_PCNT_LOW = 2 IND_SCORE_LOW = 4 a_flag = Suspicion.TOT_PCNT_LOW | Suspicion.IND_PCNT_LOW In Python before 3.10
def flag_names(flag): return [f.name for f in flag.__class__ if f & flag == f] It's slightly easier in 3.10+
def flag_names(flag): # Python 3.10+ return [f.name for f in flag] In either case:
print(flag_names(a_flag)) gets you
['TOT_PCNT_LOW', 'IND_PCNT_LOW'] If the incoming flag argument may be an integer instead of a Suspicion member, you can handle that as well:
def flag_names(flag, enum=None): """ returns names of component flags making up flag if `flag` is an integer, `enum` must be enumeration to match against """ if enum is None and not isinstance(flag, Flag): raise ValueError('`enum` must be specifed if `flag` is an `int`') enum = enum or flag.__class__ return [f.name for f in enum if f & flag == f] 
