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I have to count all executable files- done it and count files which are .sh files- no idea how to do it. Any help? Here's my code:

c=0 d=0 for f in /home/lenovo/*; do if [ -x "$f" ] ; then c=$(($c+1)) if $f . name -iname = '*.sh'; then d=$(($d+1)) fi fi done echo $c echo $d
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With a correct find command, you can do a correct and quick way to do this, for example :

find . -type f -name "*.sh"|wc -l

And you can set more arguements in find to be more efficient (for example -maxdepth -mindepth or -ctime or -executable or -perm that could be intersting too in you use case)

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Could it be as simple as ls /home/lenovo/*.sh | wc -c? Or do you have other requirements?

This would count any file ending with .'sh' whether it is executable or not.

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