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I want to check my Datatype in python using if else

Output I want : If user Enter float Datatype so it print It is float or if user enter another Datatype so it print it is not float

Code:

c=(input("Enter the value\n")) if type (c) == float: print('it is float') else: print("it is not float")

Output I want:

Enter the value 12.1 it is float

Output I'm getting:
If I enter float datatype it is still printing it is else

Enter the value 12.1 it is else
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    I think you misunderstand. The input() function always returns an object of type str. You can convert it to other types yourself if you want to. Commented Aug 14, 2021 at 15:32
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    c is always str Commented Aug 14, 2021 at 15:32
  • Does this answer your question? How to check if input is float or int? Commented Aug 14, 2021 at 15:34
  • so what can I do? if I use c=float(input("Enter a number") so it always show float. Any solution? Commented Aug 14, 2021 at 15:34

3 Answers 3

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c=input("Enter the value\n") try: float(c) print('it is float') except ValueError: print("it is not float")

your problem is that input always give you str value so by trying to convert it to float you know if its a float or not

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Comments

1

You should have something like this

c = (input("Enter the value\n")) try: f = float(c) is_float = True except ValueError: is_float = False
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Check if object is int or float: isinstance()

The type of an object can be obtained with the built-in function type().

i = 100 f = 1.23 print(type(i)) print(type(f)) # <class 'int'> # <class 'float'>

The built-in function isinstance(object, type) can be used to determine whether an object is of a particular type.

Get / determine the type of an object in Python: type(), isinstance()

print(isinstance(i, int)) # True print(isinstance(i, float)) # False print(isinstance(f, int)) # False print(isinstance(f, float)) # True

In this case, since only the type is checked, it cannot be determined whether the value of float is an integer (the fractional part is 0).

f_i = 100.0 print(type(f_i)) # <class 'float'> print(isinstance(f_i, int)) # False print(isinstance(f_i, float)) # True source: check_int_float.py Check if float is integer: is_integer() float has is_integer() method that returns True if the value is an integer, and False otherwise. f = 1.23 print(f.is_integer()) # False f_i = 100.0 print(f_i.is_integer()) # True

For example, a function that returns True for an integer number (int or integer float) can be defined as follows. This function returns False for str.

def is_integer_num(n): if isinstance(n, int): return True if isinstance(n, float): return n.is_integer() return False print(is_integer_num(100)) # True print(is_integer_num(1.23)) # False print(is_integer_num(100.0)) # True print(is_integer_num('100')) # False

Credits: https://note.nkmk.me/en/python-check-int-float/

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It is absolutely the case that one should use isinstance() rather than checking the return of type(). Thanks for bringing that up. However, in this case input() always returns a string so we can't really use isinstance() in the way we hope and a cast to float can throw an error so we really need an answer built around try: