My task is to write a function named only_ints that takes two parameters. Your function should return True if both parameters are integers, and False otherwise.
For example, calling only_ints(1, 2) should return True, while calling only_ints("a", 1) should return False.
I'm confused. How do I apply type()? Because isinstance(False, int) outputs --> True
isinstance is the right tool to be used here. bool is a private case of int and therefore we give him a special care :-)
Try (print(True + 1)) and see that the result is 2
def only_ints(x: int, y:int) -> bool: return isinstance(x, int) and not isinstance(x, bool) and isinstance(y, int) and not isinstance(y, bool) print(only_ints(4, 6)) print(only_ints(4, False)) output
True False You could use == to compare the type of a variable or value to a known type.
>>> type(True) == int False >>> type(3) == int True Before you implement only_ints using type, you should verify that you don't want True and False to be considered int. Booleans do evaluate to integer values in Python in many contexts.
You can use type and ==. isinstance sadly does not behave intuitively in this situation.
def only_ints(x,y): return type(x) == int and type(y) == int 