removing elements from a list

Question

How can i remove elements with a value of 0 as they pop upp in this loop?

y = [4, 2, 7, 9] x = input("run?") while x: for i in range(len(y)): y[i] -= 1 y.append(len(y)) print(y)

while x will put you into an infinite loop if x evaluates to True — Seth Carnegie
– Seth Carnegie, Commented Aug 10, 2011 at 19:07

Nate · Accepted Answer · 2011-08-10 19:21:01Z

you could always use a list comprehension to filter them:

for i in range(len(y)): y[i] -= 1 y = [x for x in y if x != 0] # <-- added here y.append(len(y))

EDIT:

I'm silly - these operations could even be combined as so:

while whatever: #<-- fix as suggested by comment on your question y = [z-1 for z in y if z > 1] y.append(len(y))

jtbandes · Accepted Answer · 2011-08-10 19:08:23Z

1

y = filter(lambda i: i != 0, y)

answered Aug 10, 2011 at 19:08

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1 Comment

note - filter+lambda is often said to be slower than a list comprehension; you might be interested in this related answer by Alex Martelli.