How to print Null character as a character in CPP? [duplicate]

Question

int main() { string s = "Hello\t\0world"; string k = ""; for(auto i =0; i<s.length();i++){ switch(s[i]){ case '\t': k = k + "\\t"; break; case '\0': k = k + "\\0"; break; default: k = k + s[i]; } } cout<<k; return 0; }

After null character string is ending and not able to get full solution.

Output should be: Hello\t\0world

@Jason the null isn't printed even if it made it into the string in the first place, it's replaced with \\0 — Alan Birtles
– Alan Birtles, Commented Mar 19, 2023 at 6:39

Remy Lebeau · Accepted Answer · 2023-03-19 06:33:00Z

0

The problem is in the initialization of s. The initialization will stop at the null-character embedded in the string.

You need to do the initialization in three steps:

string s = "Hello\t"; // First part of string s += '\0'; // Add the terminator character s += "world"; // Add the second part of the string

edited Mar 19, 2023 at 6:33

Remy Lebeau

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answered Mar 19, 2023 at 6:30

Some programmer dude

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2 Comments

Remy Lebeau Over a year ago

Alternatively, you could just tell the string constructor what the full length is: string s("Hello\t\0world", 12);

Richard Over a year ago

"You need to do the initialization in three steps:..." Technically the last 2 steps that uses += are not initialization.

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