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For a given table 'foo', I need a query to generate a set of tables that have foreign keys that point to foo. I'm using Oracle 10G.

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10 Answers 10

46

This should work (or something close):

select table_name from all_constraints where constraint_type='R' and r_constraint_name in (select constraint_name from all_constraints where constraint_type in ('P','U') and table_name='<your table here>'); 
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5

The following statement should give the children and all of their descendents. I have tested it on an Oracle 10 database.

SELECT level, main.table_name parent, link.table_name child FROM user_constraints main, user_constraints link WHERE main.constraint_type IN ('P', 'U') AND link.r_constraint_name = main.constraint_name START WITH main.table_name LIKE UPPER('&&table_name') CONNECT BY main.table_name = PRIOR link.table_name ORDER BY level, main.table_name, link.table_name 

3 Comments

nice use of hierarchical retrieval. However when you have tables with self referencing foreign keys, it will generate error.
This is the greatest thing ever. You just need to change the 'U' to 'R' for newer versions of Oracle.
@focusHard, I believe that adding AND main.table_name <> link.table_name to the where clause will prevent that error.
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Here's how to take Mike's query one step further to get the column names from the constraint names:

select * from user_cons_columns where constraint_name in ( select constraint_name from all_constraints where constraint_type='R' and r_constraint_name in (select constraint_name from all_constraints where constraint_type in ('P','U') and table_name='<your table name here>')); 

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1

link to Oracle Database Online Documentation

You may want to explore the Data Dictionary views. They have the prefixes:

  • User
  • All
  • DBA

sample:

select * from dictionary where table_name like 'ALL%' 

Continuing Mike's example, you may want to generate scripts to enable/disable the constraints. I only modified the 'select' in the first row.

select 'alter table ' || TABLE_NAME || ' disable constraint ' || CONSTRAINT_NAME || ';' from all_constraints where constraint_type='R' and r_constraint_name in (select constraint_name from all_constraints where constraint_type in ('P','U') and table_name='<your table here>'); 

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I know it's kinda late to answer but let me answer anyway. Some of the answers above are quite complicated hence here is a much simpler take.

SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = 'your table name' 

2 Comments

I think this works better: <pre> select a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column, a.position from user_cons_columns a join user_constraints c on a.owner = c.owner and a.constraint_name = c.constraint_name join user_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name and a.position = b.position where c.constraint_type = 'R' order by a.constraint_name, a.table_name, a.column_name, b.table_name, b.column_name
When the foreing key is over multiple columns, this query returns invalid results.
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select distinct table_name, constraint_name, column_name, r_table_name, position, constraint_type from ( SELECT uc.table_name, uc.constraint_name, cols.column_name, (select table_name from user_constraints where constraint_name = uc.r_constraint_name) r_table_name, (select column_name from user_cons_columns where constraint_name = uc.r_constraint_name and position = cols.position) r_column_name, cols.position, uc.constraint_type FROM user_constraints uc inner join user_cons_columns cols on uc.constraint_name = cols.constraint_name where constraint_type != 'C' ) start with table_name = '&&tableName' and column_name = '&&columnName' connect by nocycle prior table_name = r_table_name and prior column_name = r_column_name; 

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Download the Oracle Reference Guide for 10G which explains the data dictionary tables.

The answers above are good but check out the other tables which may relate to constraints.

SELECT * FROM DICT WHERE TABLE_NAME LIKE '%CONS%'; 

Finally, get a tool like Toad or SQL Developer which allows you to browse this stuff in a UI, you need to learn to use the tables but you should use a UI also.

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select acc.table_name, acc.constraint_name from all_cons_columns acc inner join all_constraints ac on acc.constraint_name = ac.constraint_name where ac.r_constraint_name in ( select constraint_name from all_constraints where table_name='yourTable' ); 

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All constraints for one table

select uc.OWNER, uc.constraint_name as TableConstraint1, uc.r_constraint_name as TableConstraint2, uc.constraint_type as constrainttype1, us.constraint_type as constrainttype2, uc.table_name as Table1,us.table_name as Table2, ucc.column_name as TableColumn1, uccs.column_name as TableColumn2 from user_constraints uc left outer join user_constraints us on uc.r_constraint_name = us.constraint_name left outer join USER_CONS_COLUMNS ucc on ucc.constraint_name = uc.constraint_name left outer join USER_CONS_COLUMNS uccs on uccs.constraint_name = us.constraint_name where uc.OWNER ='xxxx' and uc.table_name='xxxx' 

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Adding my two cents here.

This query will return all foreign keys with child and parent columns, matched perfectly even when there is foreign key over multiple columns:

SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name JOIN all_cons_columns b ON c.owner = b.owner AND c.r_constraint_name = b.constraint_name AND b.position = a.position WHERE c.constraint_type = 'R' 

(inspired by @arvinq aswer)

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