For a given table 'foo', I need a query to generate a set of tables that have foreign keys that point to foo. I'm using Oracle 10G.
- This article may help: http://www.databasejournal.com/features/oracle/article.php/3665591Sean– Sean2008-09-17 18:22:41 +00:00Commented Sep 17, 2008 at 18:22
- 1If you just need this info in order to drop the table, you can also use DROP TABLE xx CASCADE CONSTRAINTSSten Vesterli– Sten Vesterli2008-09-17 19:16:31 +00:00Commented Sep 17, 2008 at 19:16
10 Answers
The following statement should give the children and all of their descendents. I have tested it on an Oracle 10 database.
SELECT level, main.table_name parent, link.table_name child FROM user_constraints main, user_constraints link WHERE main.constraint_type IN ('P', 'U') AND link.r_constraint_name = main.constraint_name START WITH main.table_name LIKE UPPER('&&table_name') CONNECT BY main.table_name = PRIOR link.table_name ORDER BY level, main.table_name, link.table_name 3 Comments
AND main.table_name <> link.table_name to the where clause will prevent that error.Here's how to take Mike's query one step further to get the column names from the constraint names:
select * from user_cons_columns where constraint_name in ( select constraint_name from all_constraints where constraint_type='R' and r_constraint_name in (select constraint_name from all_constraints where constraint_type in ('P','U') and table_name='<your table name here>')); Comments
link to Oracle Database Online Documentation
You may want to explore the Data Dictionary views. They have the prefixes:
- User
- All
- DBA
sample:
select * from dictionary where table_name like 'ALL%' Continuing Mike's example, you may want to generate scripts to enable/disable the constraints. I only modified the 'select' in the first row.
select 'alter table ' || TABLE_NAME || ' disable constraint ' || CONSTRAINT_NAME || ';' from all_constraints where constraint_type='R' and r_constraint_name in (select constraint_name from all_constraints where constraint_type in ('P','U') and table_name='<your table here>'); Comments
I know it's kinda late to answer but let me answer anyway. Some of the answers above are quite complicated hence here is a much simpler take.
SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name WHERE c.constraint_type = 'R' AND a.table_name = 'your table name' 2 Comments
select distinct table_name, constraint_name, column_name, r_table_name, position, constraint_type from ( SELECT uc.table_name, uc.constraint_name, cols.column_name, (select table_name from user_constraints where constraint_name = uc.r_constraint_name) r_table_name, (select column_name from user_cons_columns where constraint_name = uc.r_constraint_name and position = cols.position) r_column_name, cols.position, uc.constraint_type FROM user_constraints uc inner join user_cons_columns cols on uc.constraint_name = cols.constraint_name where constraint_type != 'C' ) start with table_name = '&&tableName' and column_name = '&&columnName' connect by nocycle prior table_name = r_table_name and prior column_name = r_column_name; Comments
Download the Oracle Reference Guide for 10G which explains the data dictionary tables.
The answers above are good but check out the other tables which may relate to constraints.
SELECT * FROM DICT WHERE TABLE_NAME LIKE '%CONS%'; Finally, get a tool like Toad or SQL Developer which allows you to browse this stuff in a UI, you need to learn to use the tables but you should use a UI also.
Comments
All constraints for one table
select uc.OWNER, uc.constraint_name as TableConstraint1, uc.r_constraint_name as TableConstraint2, uc.constraint_type as constrainttype1, us.constraint_type as constrainttype2, uc.table_name as Table1,us.table_name as Table2, ucc.column_name as TableColumn1, uccs.column_name as TableColumn2 from user_constraints uc left outer join user_constraints us on uc.r_constraint_name = us.constraint_name left outer join USER_CONS_COLUMNS ucc on ucc.constraint_name = uc.constraint_name left outer join USER_CONS_COLUMNS uccs on uccs.constraint_name = us.constraint_name where uc.OWNER ='xxxx' and uc.table_name='xxxx' Comments
Adding my two cents here.
This query will return all foreign keys with child and parent columns, matched perfectly even when there is foreign key over multiple columns:
SELECT a.table_name child_table, a.column_name child_column, a.constraint_name, b.table_name parent_table, b.column_name parent_column FROM all_cons_columns a JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name JOIN all_cons_columns b ON c.owner = b.owner AND c.r_constraint_name = b.constraint_name AND b.position = a.position WHERE c.constraint_type = 'R' (inspired by @arvinq aswer)