Parsing JSON File Java [duplicate]

Question

I want to parse a JSON file in java and get the following values from the file mentioned below:

{ "status": "OK", "origin_addresses": [ "Vancouver, BC, Canada", "Seattle, État de Washington, États-Unis" ], "destination_addresses": [ "San Francisco, Californie, États-Unis", "Victoria, BC, Canada" ], "rows": [ { "elements": [ { "status": "OK", "duration": { "value": 340110, "text": "3 jours 22 heures" }, "distance": { "value": 1734542, "text": "1 735 km" } }, { "status": "OK", "duration": { "value": 24487, "text": "6 heures 48 minutes" }, "distance": { "value": 129324, "text": "129 km" } } ] }, { "elements": [ { "status": "OK", "duration": { "value": 288834, "text": "3 jours 8 heures" }, "distance": { "value": 1489604, "text": "1 490 km" } }, { "status": "OK", "duration": { "value": 14388, "text": "4 heures 0 minutes" }, "distance": { "value": 135822, "text": "136 km" } } ] } ] }

From every element, i want to get the value field of both distance and duration. How do i do this?

The org.json library is great for simply parsing JSON. This video shows how to parse JSON files using org.json. Hope it helps. — drorw
– drorw, Commented Nov 20, 2018 at 6:12

jake stayman · Accepted Answer · 2016-04-01 20:17:58Z

Using the json.org reference implementation (org.json homepage, Download here). The code is a bit messy but I think it does what you are asking for. You can take alot of shortcuts by not creating all this objects but to access them directly. The reason that I do it this way is an attempt to make it easier to follow whats happening.

package com.mypackage; import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject; public class Main { public static void main(String[] args) { String jsonStr = "{\"status\": \"OK\",\"origin_addresses\": [ \"Vancouver, BC, Canada\", \"Seattle, État de Washington, États-Unis\" ],\"destination_addresses\": [ \"San Francisco, Californie, États-Unis\", \"Victoria, BC, Canada\" ],\"rows\": [ {\"elements\": [ {\"status\": \"OK\",\"duration\": {\"value\": 340110,\"text\": \"3 jours 22 heures\"},\"distance\": {\"value\": 1734542,\"text\": \"1 735 km\"}}, {\"status\": \"OK\",\"duration\": {\"value\": 24487,\"text\": \"6 heures 48 minutes\"},\"distance\": {\"value\": 129324,\"text\": \"129 km\"}} ]}, {\"elements\": [ {\"status\": \"OK\",\"duration\": {\"value\": 288834,\"text\": \"3 jours 8 heures\"},\"distance\": {\"value\": 1489604,\"text\": \"1 490 km\"}}, {\"status\": \"OK\",\"duration\": {\"value\": 14388,\"text\": \"4 heures 0 minutes\"},\"distance\": {\"value\": 135822,\"text\": \"136 km\"}} ]} ]}"; try { JSONObject rootObject = new JSONObject(jsonStr); // Parse the JSON to a JSONObject JSONArray rows = rootObject.getJSONArray("rows"); // Get all JSONArray rows for(int i=0; i < rows.length(); i++) { // Loop over each each row JSONObject row = rows.getJSONObject(i); // Get row object JSONArray elements = row.getJSONArray("elements"); // Get all elements for each row as an array for(int j=0; j < elements.length(); j++) { // Iterate each element in the elements array JSONObject element = elements.getJSONObject(j); // Get the element object JSONObject duration = element.getJSONObject("duration"); // Get duration sub object JSONObject distance = element.getJSONObject("distance"); // Get distance sub object System.out.println("Duration: " + duration.getInt("value")); // Print int value System.out.println("Distance: " + distance.getInt("value")); // Print int value } } } catch (JSONException e) { // JSON Parsing error e.printStackTrace(); } } }

Bozho · Accepted Answer · 2012-01-20 09:33:45Z

Create an class structure that reflects the JSON
Use a library like Jackson or GSON to deserialize the json to instances of your classes.

If you want a more dynamic approach, the above frameworks can also serialize to maps.

shift66 · Accepted Answer · 2012-01-20 09:34:27Z

1

Use a library for working with JSON. For example google-gson.

answered Jan 20, 2012 at 9:34

shift66

12k13 gold badges54 silver badges83 bronze badges

Comments

Hemant Metalia · Accepted Answer · 2012-01-20 09:37:24Z

as Bozho said create class structure that reflacts JSON and then use jacson library as follow:

refer Parsing JSON File Java

ObjectMapper mapper = new ObjectMapper(); Projects projs = mapper.readValue(new File("projects.json"),Projects.class); ArrayList<Project> projects = projs.get("projects"); for (Project p : projects) { ArrayList<String> description = p.getDescription(); for (String s : description) { System.out.println(s);

onof · Accepted Answer · 2012-01-20 09:40:03Z

You can use a library like JSON-java

import org.json.JSONObject; String jsonString = ... JSONObject object = new JSONObject(jsonString); String status = object.getString("status");

lmo · Accepted Answer · 2018-02-02 14:02:29Z

0

You can use :

org.bson.Document d = org.bson.Document.parse("{ foo: \"bar\" }");

answered Feb 2, 2018 at 14:02

lmo

5475 silver badges25 bronze badges

Comments

touti · Accepted Answer · 2012-01-20 09:51:34Z

yes you can use jacson to parse it but there is more easy way to do it its Jsonme lib "import org.json.me" you dont have to add jar file to use it

 JSONObject obj = new JSONObject("{'var1':'val1','var2':200}); String var1=obj.getString("var1"); int var2=obj.getInt("var2");

yes its more easy but if your project is complex i advice you to use jacson lib

Collectives™ on Stack Overflow

Parsing JSON File Java [duplicate]

7 Answers 7

Comments

Comments

Comments

Comments

Comments

Comments

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

7 Answers 7

Comments

Comments

Comments

Comments

Comments

Comments

Comments

Linked

Related