Better way to assign values to multidimensional array

Question

this must be answered some time in the past, however I could not a particular way that I was looking for. I want to make an array dimension of 7 x 2;

ex)

{0,0} {0,0} {0,0} ... ... .. .

int [,] myArray = new int[7,2];

Then I tried to treat each dimension of an array like one dimensional array. So I tried to assign values to the array this way...

int[0] = new int{ 1, 2};

I think it should then look like... {1 , 2} {0 , 0} ... .. . but i get an error.

I believe it is due to my incomplete understanding of an array class.

Chris Shain · Accepted Answer · 2012-02-02 22:14:20Z

What you want is a jagged array, not a multidimentional array. Essentially, an array of arrays:

int[][] myArray = new int[7][]; int[0] = new int {1, 2};

The second "dimension" arrays are not bounded to a length of 2 however- you need to enforce that manually. This is why they are called jagged- visually, they can be of varying lengths:

{ { 3, 2 }, { 1, 8, 3 }, { 9, 6, 3, 4 }, { 4, 2, 8 }, { 4, 9, 3, 4, 5 }, { 2, 2 } }

All about arrays in C# here: http://msdn.microsoft.com/en-us/library/aa288453(v=vs.71).aspx

Hans Jonus · Accepted Answer · 2012-02-02 22:18:10Z

2

Here's how you can do it for your case:

int [,] arr = new [,] { {0,1}, {1,2} };

answered Feb 2, 2012 at 22:18

Hans Jonus

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Community · Accepted Answer · 2020-06-20 09:12:55Z

You may use the proposition of Chris Shain, or stay with your approach which is Multidimensional array.

To initialize such array

int [,] myArray = new int[3,2] {{1,2},{3,4},{5,6}};

or omit the dimension parameters

int [,] myArray = new int[,] {{1,2},{3,4},{5,6}};

You problem was with accessing to the array elements, in multidimensional array you access directly to the element for example

myArray[1,1] = 7;

will change the 1 into 7;

All this and even more you will find in documentation of Arrays.

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