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Uh. Each byte has 8 (eight) bits (on a typical general-purpse CPU). You are assigning each of your 4 (four) bytes (4*8==32 bits total) a value that consists of 5 (five) one-bits and 3 (three) zero-...

Two (unrelated) things: sizeof(char) is defined by the C specification to always be equal to 1 (no matter the actual sizer in bits of char); For any pointer (or array) p and index i, the expression *(...

Side notes, sizeof(char) is defined as 1 and so it can be omitted (though learning to always include the size as part of the size argument is helpful). Also, *(mmry_ptr+i) is simply mmry_ptr[i], the ...

As of C23, this is indeed undefined behavior. If you want to store objects of another type in a char array, you would have to use memcpy for every reading and writing access. But this will change in ...

One big problem with binary serialization is when you have to deal with different endian representations between the serializer and deserializer. In such an environment it almost impossible to just ...