When using \psplot in PS form (or algebraic=false) the interval must be specified in degrees. However, sometimes, I need algebraic=false but interval is given in radian. Is it possible to achieve this scenario?
The following code shows that the output of plotting r=2^(x/2) (radius as a function of angle x) with algebraic=false and algebraic=true are different because PSTricks assumes that interval in first case is in degrees.
\documentclass[preview,border=12pt]{standalone} \usepackage{pst-plot} \psset{polarplot} \begin{document} \begin{pspicture}[showgrid=true](-3,-3)(3,3) \psplot{2 Pi mul neg}{2 Pi mul}{2 x 10 div exp} \end{pspicture}\qquad \begin{pspicture}[showgrid=true](-3,-3)(3,3) \psplot[algebraic]{2 Pi mul neg}{2 Pi mul}{2^(x/10)} \end{pspicture} \end{document} 
How to make a radian argument still get interpreted in radian when working with \psplot in PostScript form?
pst-plot.texcontains a lineF@pstplot x \ifPst@algebraic RadtoDeg \fi PtoC, so this conversion foralgebraic=trueis fixed. Bug or feature, this may be answered by @Herbert.\psplot[polarplot]{<RPN>}{<RPN>}{<RPN>}to plot a graph ofr=f(t)=a^tfor example.