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Can you explain why TikZ places the node center incorrectly in this MWE? I expect the red node to overlap the black one entirely, but it does not. If I remove the scaling, the problem goes away.

\documentclass[tikz, border=10]{standalone} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{tikzpicture}[xscale=-100,yscale=-100] \tikzstyle{every node}=[inner sep=0pt,outer sep=1pt,minimum size=2mm,draw=black,fill=black,circle] \node (A) at (2,2) {}; \node at (A.center) [red] {}; \end{tikzpicture} \end{document}

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  • Use \begin{tikzpicture}[xscale=-100,yscale=-100,transform shape] for more surprises. Commented Apr 10, 2015 at 0:29
  • I am not so good with tikz but aren't you placing the bottom left corner of the red node at the center of the black node? Commented Apr 10, 2015 at 1:06
  • @MatoBehr No, the coordinate you give it is the center of the node. Commented Apr 10, 2015 at 2:03
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    This seems to be caused by a rounding error when TikZ is scaling and retrieving the coordinates for the center of the node. You can repeat this by writing \node (B) at (A.center) [red] {}; and then create a node C etc. Then examine the coordinates for the center of these nodes using: \foreach \myn in {A,B,C} {\pgfextractx\aex{\pgfpointanchor{\myn}{center}} \pgfextractx\aey{\pgfpointanchor{\myn}{center}} \typeout{==> \myn ==> [\the\aecm]\the\aex,\the\aey}} where \aex, \aey, and \aecm are lengths, and \aecm has length 1 cm. Commented Apr 10, 2015 at 4:06
  • The problem is just barely visible at scale=10, while scale=8 looks fine. Commented Apr 10, 2015 at 4:20

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try this

\documentclass[tikz, border=10]{standalone} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{tikzpicture}[xscale=-100,yscale=-100] \tikzstyle{every node}=[inner sep=0pt,outer sep=1pt,minimum size=2mm,draw=black,fill=black,circle] \coordinate (a) at (2,2); \node (A) at (a) {}; \node (B) at (a) [red] {}; \end{tikzpicture} \end{document}
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