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In the minimal example below, the commented out line does not work. Other lines work correctly. I can't understand what the reason is.

Here is a similar question, but my variable \im takes integer values.

\documentclass[margin=3mm]{standalone} \usepackage{tikz} \usepackage{ifthen} \begin{document} \begin{tikzpicture} \def\m{12} \def\n{13} \foreach \i in {0,...,\m}{\coordinate[label=] (u\i) at (360*\i/\n:1);} \foreach \i in { 0,...,\m}{% \pgfmathMod{\i}{5}\edef\im{\pgfmathresult} \draw[blue] (u\im) circle (0.04); \ifthenelse{\i =0}{ }{\draw[red,fill] (u\i) circle (0.02);} %\ifthenelse{\im=0}{ }{\draw[green,fill] (u\i) circle (0.01);} } \end{tikzpicture} \end{document}
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    \im is a float, you can convert it to int with \pgfmathMod{\i}{5}\pgfmathint{\pgfmathresult} Commented Apr 10, 2024 at 9:41

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If you add \show\im after the \edef, you'll see at the first cycle

> \im=macro: ->0.0.

and

> \im=macro: ->1.0.

at the second cycle. This cannot work with \ifthenelse, that expects integers.

Use \pgmathtruncatemacro{\im}{mod(\i,5)} instead.

\documentclass[margin=3mm]{standalone} \usepackage{tikz} \usepackage{ifthen} \begin{document} \begin{tikzpicture} \def\m{12} \def\n{13} \foreach \i in {0,...,\m}{\coordinate[label=] (u\i) at (360*\i/\n:1);} \foreach \i in { 0,...,\m}{ \pgfmathtruncatemacro{\im}{mod(\i,5)} \draw[blue] (u\im) circle (0.04); \ifthenelse{\im=0}{}{\draw[green,fill] (u\i) circle (0.01);} } \end{tikzpicture} \end{document}

enter image description here

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  • In general it is strange that the mod function returns a non integer value. But `\pgfmathtruncatemacro{\im}{mod(\i,5)}' works thank you very much. And here's another thing. Why are the blue circles drawn correctly \draw[blue] (u\im) circle (0.04);? Commented Apr 10, 2024 at 10:49
  • @kabenyuk The “mod” function can also be used with nonintegers. Commented Apr 10, 2024 at 13:10

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