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I have a file of the following form (with '-' serving as delimiters), and I want to find the appearance of a number only when it follows a delimiter. I suppose it's a concatenation of grep '-\n' and $number, but I can't find the way to do it right. thanks..

1400 2 132 342 - 76567 1 1234 - 87 2 1400 54 -
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    By modifying your question like that 3 months later, you're invalidating all the answers you've received. It's also unlikely that people will notice that you've changed the requirements. It would be better to ask a separate question. Commented Jun 17, 2014 at 22:01

5 Answers 5

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To find variable before the delimiter:

Using awk:

$ awk '/!!!!!!!!!!!/{print num}{num=$0}' inputFile 342 1234 54

or gnu-awk:

$ gawk 'NF && $0=$NF' RS='[!]+' inputFile 342 1234 54

To find variable after the delimiter:

Using awk:

$ awk '/!!!!!!!!!!!/{if(getline) print $0}' inputFile 76567 87

or gnu-awk:

$ gawk 'NR>1 && $0=$1' RS='[!]+' inputFile 76567 87
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  • we can shorten your version: awk '/!!!!!!!!!!!/{if(getline){print}}' file Commented Mar 16, 2014 at 13:20
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    Good that you have provided both the variants; given that the question doesn't make it clear! Commented Mar 16, 2014 at 13:23
  • Thanks @devnull. Yea, I was pretty much certain what I had in earlier was what OP wanted until a new answer came in which completely threw my understanding of the question. So went with both! :) Commented Mar 16, 2014 at 13:25
  • @jaypalsingh The level of tolerance for not-so-good-quality-posts is considerably higher on this site in comparison to SO. As such, rather vague questions keep getting attracted. Commented Mar 16, 2014 at 13:31
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    @jaypalsingh nice!!!!!! :D Commented Mar 16, 2014 at 13:33
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The following command 

grep '!!' -A 1 file|grep -vE '!!|\-\-'

will yield 

76567 87
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  • You read my mind... Commented Mar 16, 2014 at 13:12
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grep has a switch -A that tells it to print a number of lines after the match. In this case, just use -A 1 and you'll get ouptut like

!!!!!!!!!!! 76567 -- !!!!!!!!!!! 87 -- !!!!!!!!!!!

Now just grep out the numbers with | grep -e '[0-9]'.

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  • grep --no-group-separator -A1 '!' inputFile | grep -v '!' would be better. Commented Mar 16, 2014 at 14:19
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using AWK

To find variable before the delimiter:

awk '{ print $NF }' RS='!!!!!!!!!!!' infile

Output

342 1234 54

To find variable after the delimiter:

awk 'NR>1{ print $1 }' RS='!!!!!!!!!!!' infile

Output

76567 87
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This does a number before a delimiter:

sed -n '/[^0-9]/!h;/^-$/{g;/./p}'

And this after:

sed -n '/^-$/{n;/./!d;/[^0-9]/!p}'
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