Delete lines from a file

Question

I have a file where data is present in below format :

cat file.txt 02|123 04|321 08|453 09|364 01|789 23|765

so here 02,04 ... represents Hour and 123,321 ... represents some random value.

I want to delete all the lines from this file where first two value is less than the current hour which will get from date +'%H'.

Suppose current hour is 10 so i want to delete lines containing first two less than 10 i.e

02|123 04|321 08|453 09|364 01|789

you can modify the answer for THIS QUESTION to suit your needs. Just use awk -F "|" to specify your field delimiter and compare the $1 to the current hour as in that answer — MelBurslan
– MelBurslan, Commented Mar 10, 2016 at 18:26

steeldriver · Accepted Answer · 2016-03-10 19:50:05Z

6

#!/bin/bash HOUR=`date +%H` awk -v hour=$HOUR -F"|" '{if($1 >= hour)print}' file.txt > newfile.txt mv newfile.txt file.txt

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answered Mar 10, 2016 at 18:39

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