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I have list extracted from a json output as below.

"Rel_70" "Rel_71" "Dev_795" "Dev_796" "Dev_797" "Devtest_10" "Devtest_12"

Out of this, I want to extract values with Dev_* i.e I am interested to extract all values "Dev_795" "Dev_796" "Dev_797" .

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  • The original JSON document that the values in the question are extracted from would be good to see. It would be easier to work with that than with a line of text with no structure. Commented Jul 11, 2021 at 7:14

3 Answers 3

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To include all "Dev_[digits]" entries:

awk 'BEGIN {RS=" "} /Dev_[0-9]+/ {print}' inputfile

Or, if you wanted specifically only to include those "Dev" entries:

awk 'BEGIN {RS=" "} /Dev_(795|796|797)/ {print}' inputfile
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tr ' ' '\n' < jsonfile | grep '"Dev_' perl -lne 'print for /"Dev_\d+"/g' jsonfile while read -ra A; do for a in "${A[@]}"; do case $a in '"Dev_'* ) echo "$a" ;; esac; done; done < jsonfile
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  • Can you put at least some prose around these answers so that the technically less competent have at least some chance of understanding what is going on here? Commented Jun 29, 2017 at 18:28
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awk 'ORS=" "{for(i=1;i<=NF;i++){if($i ~ /Dev_/){print $i}}}' filename

output

"Dev_795" "Dev_796" "Dev_797"
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