Is there a way to return a list of all folders on a given disk containing more than X images ?
The search should be recursive but X should not.
Example for X=100 :
Folder A |_ folder A1 (containing 100 pictures) |_ folder A2 (containing 50 pictures) |_ 50 pictures Should return "Folder A1" only.
I am assuming all the pictures end with .png and X=100
find ./ -type d -exec sh -c 'count=$(ls "${0}"/*.png | wc -l); if [ "${count}" -ge 100 ];then echo "${0}"; fi ' {} \; EDIT
It can be extended for files for any number of extensions and any value of X like below
export files='png jpg gif' export X='100' find ./ -type d -exec \ sh -c 'count=$(for i in ${files}; do ls "${0}"/*.${i};done | wc -l); \ if [ "${count}" -ge "${X}" ];then echo "${0}"; fi ' {} \; for each image, print the name of the directory it lies in:
find \( -name \*.png -or -name \*.gif -or -name \*.jpg \) -printf '%h\n' | uniq needs sorted input, but find prints files rather randomly. (In my test, even find -depth didn't help, don't ask me why.)
sort | for every directory name, tell us how often it occurs:
uniq -c | and finally, filter the lines we want:
while read count dir; do if [ "$count" -ge 100 ]; then echo "$count $dir"; fi done 