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My programm can have the following format:

<command_name> <arguments> <options> -hosts <host1> <host2> ... <hostn> (<more_arguments>) ...

I am trying to set bash auto-completion, and based on debian-administration's article, I have done host completion like this :

(...) case "${prev}" in -hosts) _known_hosts_real -a "$cur" return 0 ;; (...) (...)

Of course after writing -hosts bash is able to complete the name of a single host, but not multiple hosts. Is there a beautiful way to achieve this hack without completing hosts when we deal with other arguments than -hosts?

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  • try to read multiple command line of being supported by auto completed , and rewrite your autocompletion. Commented Nov 19, 2014 at 17:17
  • Why is zsh tagged? Commented Nov 19, 2014 at 18:08
  • My bad, I thought it was kind of similar. Commented Nov 20, 2014 at 8:02

2 Answers 2

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If you ignore the (<more_arguments>) case then you can just check whether -hosts is one of the earlier words: 

(...) for ((i=1;i<COMP_CWORD;i++)); do if [ "-hosts" == "${COMP_WORDS[i]}" ]; then _known_hosts_real -a "$cur" return 0 fi done case "${prev}" in
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  • Thanks, I am using this hack for the moment. Some alternatives may exist, avoiding to check every word and considering the <more_arguments> case. Commented Nov 20, 2014 at 8:05
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I'm not sure if it's possible to create such autocompletion rule for space-separated hosts values. But if you don't mind using comma-separated lists then:

_myhost () { local cur prev opts _get_comp_words_by_ref cur prev opts='-hosts' servers='name1 name2 name3' if [[ ${cur} == -* ]] ; then COMPREPLY=( $(compgen -W "${opts}" -- ${cur}) ) else case "${prev}" in -hosts) if [[ "$cur" == *,* ]]; then local realcur prefix realcur=${cur##*,} prefix=${cur%,*} COMPREPLY=( $(compgen -W "${servers}" -P "${prefix}," -- ${realcur}) ) else COMPREPLY=( $(compgen -W "${servers}" -- ${cur}) ) fi ;; *) # do nothing ;; esac fi } complete -F _myhost myhost
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