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I'm using bash shell on Amazon Linux. I have a command in a shell script

wget -O - "http://localhost:8088/subco/books/$e_id/segments/$segment_id?product=$product_id&audience=teacher" > /dev/null

Reading this -- https://superuser.com/questions/321240/how-do-you-redirect-wget-to-standard-out/321241, I was led to believe I could output the result of wget (what it retrieves) to my screen and suppress all other output. However instead, what I get is

--2018-05-29 18:39:49-- http://localhost:8088/subco/books/C2644BB08F394E209A26175BD2C89F5A/segments/C2F62E7002964DD396E381DB331129A4?product=D399B9C5F6204EDE80A002930CC0D02F&audience=teacher Resolving localhost (localhost)... 127.0.0.1 Connecting to localhost (localhost)|127.0.0.1|:8088... connected. HTTP request sent, awaiting response... 200 OK Length: unspecified [text/html] Saving to: ‘STDOUT’

How do I output the result of wget to the screen and suppress all other information (e.g. like the "HTTP request sent, awaiting response... 200 OK" part)?

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If you want to use wget, the use -qO - 

wget -qO - google.com

Or you could use curl with no options

curl google.com

And if you want to go a little further and parse results etc, the package BeautifulSoup for Python is great.

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  • thanks for the curl suggestion, it's the perfect tool for my use case. Commented Jan 5, 2021 at 15:41
  • what if you want to issue a POST request? Commented Nov 2, 2021 at 9:37

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