I have the issue to extract the x amount of characters from string and i have the difficulty enlarging the capability of the expression.
I have tried to use the sed command.
If i have the string example.com.db i need to keep "example.com",for that i use
sed 's/\.db//g' How to change expression so that i can use these kind of files too example.db.db.com.db.
in this case the end result i need is example.db.db.com
you can use:
's/.db$//' alternatively you can use:
's/...$//' to remove the last 3 characters and
's/\.[^\.]*$//' to remove the everything after the last dot
's/\.[^.]*$//' You were close, use the Regex syntax $ to indicate the end of the line, also no need for the global (g) modifier as you are trying to find only one match :
sed 's/\.db$//' file.txt Example :
$ sed 's/\.db$//' <<<'example.db.db.com.db' example.db.db.com $ sed 's/\.db$//' <<<'example.db.com.db' example.db.com To remove last three characters from string
sed 's/.\{3\}$//' Example
% sed 's/.\{3\}$//' <<< "example.db.db.com.db" example.db.db.com In sed, $ matches the end of line, so you can try
echo example.db.db.com.db | sed 's/\.db$//' Note that I backslashed the dot to match literally, otherwise it matches any character.
