JavaScript, 68 bytes

s=>'RedOrangeYellowGreenBlueIndigoVioletRed'.match(s+'(.[a-z]*)')[1] 

For input "Red", this function first construct an RegExp /Red(.[a-z]*)/ to match the string 'RedOrangeYellowGreenBlueIndigoVioletRed' and then return the first capture result.

f= s=>'RedOrangeYellowGreenBlueIndigoVioletRed'.match(s+'(.[a-z]*)')[1] document.write('<table><tr><th>Input<th>Output') for(i='Red';;){ document.write(`<tr><td>${i}<td>${i=f(i)}`); if(i=='Red')break; }

Perl 5 -p, 58 57 bytes

#!/usr/bin/perl -p $_={(Red,Orange,Yellow,Green,Blue,Indigo,Violet)x2}->{$_} 

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Now that the challenge has been changed to be cyclic the regex solution

say RedOrangeYellowGreenBlueIndigoVioletRed=~/$_(.[a-z]+)/ 

isn't optimal anymore (due to the double Red)

Also 57 bytes:

#!/usr/bin/perl -p $_=(Indigo,Blue,Violet,Yellow,Orange,Red,Green)[ord>>2&7] 

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Python, 79 bytes

z="Red Orange Yellow Green Blue Indigo Violet".split()*2 dict(zip(z,z[1:])).get 

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Handles Violet -> Red. The desired function is given anonymously in the second line.

80 bytes

lambda x:"Red Orange Yellow Green Blue Indigo Violet Red".split(x)[1].split()[0] 

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Perl 6, 56 bytes

{<Indigo Blue Violet Yellow Orange Red Green>[.ord/4%8]} 

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Exploits the fact that bits 2-4 of the ASCII codes of each color's first letter happen to map to 0-6.

say map (*.ord +> 2) % 8, <R O Y G B I V> # (4 3 6 1 0 2 5) 

Here's a nice non-competing solution that uses "purple" instead of "indigo" and "violet" (38 chars, 59 bytes):

{'🍎🧡💛💚💙💜🍎'.uninames~~m/$^a.\S+.<(\S+/} 

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05AB1E, 30 bytes

“†¾›ÈŠÛˆ¨‡—ëßigo°Íolet“#™DIk>è 

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Explanation

“†¾›ÈŠÛˆ¨‡—ëßigo°Íolet“ # push a string of colours # # split on spaces ™ # title-case each D # duplicate Ik # get the index of the input > # increment è # get the element at that index 

Ruby -n, 62 60 bytes

-2 by Asone Tuhid.

p"RedVioletIndigoBlueGreenYellowOrangeRed"[/.[a-z]+(?=#$_)/] 

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Regex approach looks promising for Ruby too. However, I arrived at a shorter solution using a lookahead and directly printing the match, rather than playing with capturing groups. The list of colors is in reverse direction since lookahead is 1 byte cheaper than lookbehind.

Red, 87 bytes

func[c][print first find/tail[Red Orange Yellow Green Blue Indigo Violet Red]to-word c] 

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Excel, 85 bytes

=CHOOSE(MOD(CODE(A1),12),"green","indigo","yellow",,,"orange","blue",,"violet","red") 

Uses lowercase names.

Same approach, with Uppercase letters 86 bytes:

=CHOOSE(MOD(CODE(A1),12),"Violet","Red",,,"Green","Indigo","Yellow",,,"Orange","Blue") 

Haskell, 80 71 75 bytes

^{Thanks to Laikoni for shortening 9 bytes!}

g x=snd(span(/=x)$words"Red Orange Yellow Green Blue Indigo Violet Red")!!1 

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Another solution, slightly more idiomatic, but I could not get it shorter:

data R=Red|Orange|Yellow|Green|Blue|Indigo|Violet deriving(Enum,Read,Eq) succ.read 

It needs to derive Read because of the requirement that the input is a string and at least Eq or Show in order to either test for equality or show the result.

Retina, 65 58 bytes

$ (.[a-z]+) L$:`RedOrangeYellowGreenBlueIndigoVioletRed $1 

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Explanation

$ (.[a-z]+) 

We start by appending (.[a-z]+) to the input, thereby turning it into a regex which matches the input colour, immediately followed by exactly one more colour (capturing the latter).

L$:`RedOrangeYellowGreenBlueIndigoVioletRed $1 

Now the : swaps the stage's input with its own regex. So the previous result becomes the regex and it's matched against the list of colours. The (single) match gets replaced with its first capturing group (i.e. the next colour in the cycle) and returned. Output at the end of the program happens automatically.

Vim, 59 56 53 52 Bytes

-1 byte thanks to tsh

2IYellow Green Blue Indigo Violet Red Orange <Esc>*wywVp

Java (JDK 10), 77 bytes

s->"Red Orange Yellow Green Blue Indigo Violet Red".split(s)[1].split(" ")[1] 

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Credits

• -10 bytes thanks to Kevin Cruijssen
• -1 byte thanks to Okx

Coconut, 79 bytes

s->"# Violet Red # # Green Indigo Yellow # # Orange Blue".split()[ord(s[0])%12] 

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Husk, 28 bytes

S!o→€⁰w¨ṙ}ΘΞĠ«ẇ₇G²€ḃλBżḃIÿö⌉ 

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Maybe there are better options for managing the arguments, but this is the best I could find

Explanation

S!o→€⁰w¨ṙ}ΘΞĠ«ẇ₇G²€ḃλBżḃIÿö⌉ ¨ṙ}ΘΞĠ«ẇ₇G²€ḃλBżḃIÿö⌉ Compressed string with all the colors "Red Orange Yellow Green Blue Indigo Violet" w Split on spaces S Pass the list to both the following functions: €⁰ 1) Find the index of the input in the list o→ and increase it by one ! 2) Get the element of the list at the resulting position (indexing is cyclical) 

Stax, 31 30 29 bytes

ÇôF┘≡▓ƒ◄╙>┘☼░⌂╪B<U[ÇQ╒eöΣQ╔÷n 

Run and debug it

This uses the ring translation instruction. It replaces each element in an array with the following one from the "decoder ring". Usually, it's used to do character replacement in a string, but it can be used on an entire string too, if it's wrapped in a singleton array.

Here's the unpacked, ungolfed, commented ascii representation of the same program.

] wrap input in singleton array `5^bZ_9G*h]h%oM~X9e-0ZQJkb2` compressed string literal with color names :.j title case and split on spaces :t do ring translation 

Run this one

J, 67 64 62 bytes

-2 bytes thank to FrownyFrog

>:&.((cut'Red Orange Yellow Green Blue Indigo Violet Red')i.<) 

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R, 109 93 bytes

function(x){y=c("Red","Orange","Yellow","Green","Blue","Indigo","Violet");y[match(x,y)%%7+1]} 

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-16 thanks to Giuseppe for the use of match advice

Batch, 97 bytes

@set s=Red Orange Yellow Green Blue Indigo Violet Red @call set s=%%s:*%1 =%% @echo %s: =&rem % 

Explanation: The call on the second line has the effect of substituting the parameter into the command and evaluating it, turning it into e.g. set s=%s:Red =%, which deletes the prefix of the string that includes the parameter. The substitution on the third line then replaces all the spaces with statement separators and comments. This works because string substitution happens before parsing.

Ruby -n, 75 69 bytes

a=%w{Red Orange Yellow Green Blue Indigo Violet};p a[-~(a.index$_)%7] 

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Julia 0.6, 76 bytes

f(s)=match(Regex("$s(.[a-z]*)"),"RedOrangeYellowGreenBlueIndigoViolet"^2)[1] 

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This handles the Violet->Red by recycling the string with the power ^ operator.

Here's a slightly longer solution without regexes:

g(s,l=split("Red Orange Yellow Green Blue Indigo Violet"," "))=l[(findin(l,[s])[1])%7+1] 

PowerShell, 74 bytes

(-split("Red Orange Yellow Green Blue Indigo Violet "*2-split$args)[1])[0] 

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Takes the string "Red ... Violet " and string-multiplies it out by two to properly handle the Violet -> Red test case. We then -split that string on input $args to give us an array of two strings. We take the second string thereof [1], then -split that on whitespace to give us an array of strings and take the first [0].

For example, for input "Yellow", the first step will result in @("Red Orange ", " Green Blue Indigo ... Indigo Violet "). We take the second one of that, split it on whitespace (which removes the whitespace), resulting in @("Green", "Blue", ... "Violet"), so taking the [0] one thereof results in the proper next string.

IBM/Lotus Notes Formula Language, 79 74 bytes

@Left(@Right("Red Orange Yellow Green Blue Indigo Violet Red ";a+" ");" ") 

Previous version for 79:

R:=@Explode("Red,Orange,Yellow,Green,Blue,Indigo,Violet,Red");R[@Member(a;R)+1] 

Takes input from an editable text field called a.

There is no TIO for formula language so here's a couple of screenshots.

PHP, 92 bytes

$a=" Red OrangeYellowGreen Blue IndigoVioletRed";echo substr($a,strpos($a,$argv[1])+6,6) 

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Kotlin, 73 bytes

x->"RedOrangeYellow Green BlueIndigoVioletRed".substringAfter(x).take(6) 

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Taking advantage of the fact that many colors are 6 characters, the ones that are not are prefixed with spaces to make them 6 characters long. Hopefully it's acceptable that some of the colors are outputted with spaces before them.
e.g. Red is " Red", Blue is " Blue"

SmileBASIC, 94 84 bytes

C$="Red OrangeYellowGreen Blue IndigoViolet INPUT I$?MID$(C$*2,INSTR(C$,I$)+6,6) 

Gema, 67 characters

*=@subst{*\?<J>=\?\$2\;\?=;RedOrangeYellowGreenBlueIndigoVioletRed} 

Sample run:

bash-4.4$ echo -n Yellow | gema '*=@subst{*\?<J>=\?\$2\;\?=;RedOrangeYellowGreenBlueIndigoVioletRed}' Green bash-4.4$ echo -n Violet | gema '*=@subst{*\?<J>=\?\$2\;\?=;RedOrangeYellowGreenBlueIndigoVioletRed}' Red 

Gema, 59 characters

R=Orange O=Yellow Y=Green G=Blue B=Indigo I=Violet V=Red *= 

Boring one. Dumbest approach ever, but quite short.

Sample run:

bash-4.4$ gema 'R=Orange;O=Yellow;Y=Green;G=Blue;B=Indigo;I=Violet;V=Red;*=' <<< 'Yellow' Green bash-4.4$ gema 'R=Orange;O=Yellow;Y=Green;G=Blue;B=Indigo;I=Violet;V=Red;*=' <<< 'Violet' Red 

q/kdb+, 59 55 bytes

Solution:

.[!;2 8#($)`Red`Violet`Indigo`Blue`Green`Yellow`Orange] 

Examples:

q).[!;2 8#($)`Red`Violet`Indigo`Blue`Green`Yellow`Orange]"Red" "Violet" q).[!;2 8#($)`Red`Violet`Indigo`Blue`Green`Yellow`Orange]"Orange" "Red" q).[!;2 8#($)`Red`Violet`Indigo`Blue`Green`Yellow`Orange]"Blue" "Green" 

Explanation:

Create a dictionary of colour => next colour, the input is the key to the dictionary:

.[!;2 8#($)`Red`Violet`Indigo`Blue`Green`Yellow`Orange] / the solution .[ ; ] / apply multiple args to function `Red`Violet`Indigo`Blue`Green`Yellow`Orange / list of colours ($) / convert to strings 2 8# / reshape into 2x8 grid ! / create dictionary 

Bonus:

It's 53 bytes in K4:

.[!;2 8#$`Red`Violet`Indigo`Blue`Green`Yellow`Orange] 

Japt, 45 43 bytes

-2 bytes thanks to Shaggy

`R‚sOÎÁƒYÁMwsGÎ9sBluƒI˜igosVio¤t`qs g1+UbNg 

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sed, 72 bytes

s/$/%RedOrangeYellowGreenBlueIndigoVioletRed/;s/(.+)%.*\1(.[a-z]+).*/\2/ 

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Example 1:

Input:

Red Orange Yellow Green Blue Indigo Violet 

Output:

Orange Yellow Green Blue Indigo Violet Red 

Example 2:

Input:

Indigo Yellow Red Red Blue Green Orange Violet Green Green Green Blue Blue Violet 

Output:

Violet Green Orange Orange Indigo Blue Yellow Red Blue Blue Blue Indigo Indigo Red