Maximum of three values in C++ [closed]

If you have access to C++11, I'd suggest using std::max with an initializer_list<T>. A complete minimal example:

#include <algorithm> #include <initializer_list> #include <iostream> int main() { int a = 1; int b = 2; int c = 3; int m = std::max({a, b, c}); std::cout << m << "\n"; } 

Assuming you have an unknown set of data, you can always place it in an array / vector / list and run...

int res = *max_element( intList.begin(), intList.end() ); //where intList is the list 

Which is as commented by @Yuushi : but expended on, since it can get quirky

#include <algorithm> #include <iostream> #include <list> #include <stdlib.h> #include <algorithm> // std::max using namespace std; int main() { list<int> intList; int a, b; int maxItems = rand() % 40 + 10; //10 to 50 items cout << "=== Testing a maximum of " << maxItems << " values ===\n"; cout << "generating random value set: {"; for( a = 0; a < maxItems; ++a ) { b = rand() % 100; cout << b << ", "; intList.push_back(b); } cout << "}\n"; //Note max element inputs iterators, and outputs the max value iterator! //-> which is the pointer to the actual value (hence * to get value) a = *max_element( intList.begin(), intList.end() ); cout << "max value generated = " << a << "\n"; return 0; } 

Which can give a sample result as below

=== Testing a maximum of 33 values === generating random value set: {86, 77, 15, 93, 35, 86, 92, 49, 21, 62, 27, 90, 59, 63, 26, 40, 26, 72, 36, 11, 68, 67, 29, 82, 30, 62, 23, 67, 35, 29, 2, 22, 58, } max value generated = 93 

A simpler way would be to use this overloaded function std::max that accepts an object of the type std::initializer_list<int>

#include<iostream> #include<algorithm> using namespace std; int main() { int a = 2; int b = 3; int c = 4; cout << max({a,b,c}) << '\n'; cout << max({7,7,8}) << '\n'; return 0; }