I would like to know the differences between:
linearSVC()SVC(kernel='lineaer)SVC(kernel='poly', degree=1)
Will these all determine the same boundary decisions?
$\begingroup$ $\endgroup$
Add a comment |
2 Answers
$\begingroup$ $\endgroup$
You can see in the user guide that the first two will not produce the same results. In the multiclass setting, LinearSVC uses one-vs-rest while SVC uses one-vs-one. Aside from that, the solver used is also different, and because of that some of the options differ. See LinearSVC docs, SVC docs.
I suspect the third will be the same as the second. I don't see anything in the source to indicate it quickly, but it shouldn't take long to test.
$\begingroup$ $\endgroup$
None of them are the same. linearSVC() uses one-vs-rest and SVC(kernel='linear) uses one-vs-one for classification.
To have the same results with the SVC poly kernel as with the SVC linear we have to set the gamma parameter to 1 otherwise the default is to use 1 / (n_features * X.var) weakening the value from the now linear kernel.
