RegExp.prototype.global

Try it

const regex1 = /foo/g; console.log(regex1.global); // Expected output: true const regex2 = /bar/i; console.log(regex2.global); // Expected output: false 

Description

RegExp.prototype.global has the value true if the g flag was used; otherwise, false. The g flag indicates that the regular expression should be tested against all possible matches in a string. Each call to exec() will update its lastIndex property, so that the next call to exec() will start at the next character.

Some methods, such as String.prototype.matchAll() and String.prototype.replaceAll(), will validate that, if the parameter is a regex, it is global. The regex's [Symbol.match]() and [Symbol.replace]() methods (called by String.prototype.match() and String.prototype.replace()) would also have different behaviors when the regex is global.

The set accessor of global is undefined. You cannot change this property directly.

Examples

Using global

const globalRegex = /foo/g; const str = "fooexamplefoo"; console.log(str.replace(globalRegex, "")); // example const nonGlobalRegex = /foo/; console.log(str.replace(nonGlobalRegex, "")); // examplefoo 

Specifications

Browser compatibility

See also

• RegExp.prototype.lastIndex
• RegExp.prototype.dotAll
• RegExp.prototype.hasIndices
• RegExp.prototype.ignoreCase
• RegExp.prototype.multiline
• RegExp.prototype.source
• RegExp.prototype.sticky
• RegExp.prototype.unicode