I have created a custom block in the Drupal CMS. Say it is called "test_block". Is there a way to render this block in a template file using the name of the block?
Thanks,
- Here Follow this postshrish– shrish2014-07-07 09:56:10 +00:00Commented Jul 7, 2014 at 9:56
- I have post my answer please have a look.Chirag Shah– Chirag Shah2014-07-07 10:42:24 +00:00Commented Jul 7, 2014 at 10:42
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5 Answers
D7:
<?php $block = module_invoke('module_name', 'block_view', 'block_delta'); print $block['content']; ?> 'module_name' = The machine name of the module (i.e. the module's folder name). This is true for core modules too, so for instance 'search', 'user' and 'comment' would all work here.
'block_delta' = The machine name of the block. You can determine what this is by visiting the block administration page and editing the block. The URL for editing a webform block, for instance, would be something like:
Drupal 7: admin/structure/block/manage/webform/client-block-11/configure
In this example, 'webform' is the module's name, 'client-block-11' is the block's delta.
Custom blocks will have module name of 'block' and a number for a delta, which you can also find by editing the block.
More information: http://drupal.org/node/26502
====== OR =============
<?php //suppose 98 is the id of the block $block =block_load('block',98); $output = drupal_render(_block_get_renderable_array(_block_render_blocks(array($block)))); print $output; ?> 
- 1The D7 solution won't universally work, because $block['content'] might be a renderable array instead of a string of html. Also, this method will only render the content, without the '#theme' => 'block' wrapper.donquixote– donquixote2018-08-09 11:33:14 +00:00Commented Aug 9, 2018 at 11:33
- The other D7 solution will cause a notice or sth, because drupal_render() has a by-reference parameter.donquixote– donquixote2018-08-09 12:29:06 +00:00Commented Aug 9, 2018 at 12:29
- See drupal.org/project/drupal/issues/957038#comment-12723048donquixote– donquixote2018-08-09 12:29:11 +00:00Commented Aug 9, 2018 at 12:29
D8:
$block_entity = Drupal\block_content\Entity\BlockContent::load(BLOCK_ID);// BLOCK_ID $block_view = \Drupal::entityTypeManager()->getViewBuilder('block_content')->view($block_entity, 'DISPLAY_VIEW_NAME'); $rendered_block = ['#markup' => render($block_view)]; 
Try this
$block = module_invoke('block', 'block_view', 'test_block'); print render($block['content']); 
- This doesnt solves the problem. I tried this already.Pratip Ghosh– Pratip Ghosh2014-07-07 10:17:51 +00:00Commented Jul 7, 2014 at 10:17
If you are asking how to use a custom template for this block, then the answer is:
Assuming the machine name of your block is test_block, then create a file called
block--block--test_block.tpl.php In your theme
On your template level you should be able to do something like this:
<?php $test_block = "test_block"; print views_embed_view($test_block); ?> This will display your block in the template.
