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I'm attempting to make use of wavelet scattering to analyse my signal samples.

The example IQ Wav file I am using is as follows: https://www.dropbox.com/s/dd6fr4va4alpazj/move_x_movedist_1_speed_25k_sample_6.wav?dl=0

Currently, following a guide from the Kymatio documentation, I have the following code:

import scipy.io.wavfile import numpy as np import matplotlib.pyplot as plt from kymatio.numpy import Scattering1D path = r"move_x_movedist_1_speed_25k_sample_6.wav" # Read in the sample WAV file fs, x = scipy.io.wavfile.read(path) x = x.T print(fs) # Once the recording is in memory, we normalise it to +1/-1 x = x / np.max(np.abs(x)) print(x) # Set up parameters for the scattering transform ## number of samples, T N = x.shape[-1] print(N) ## Averaging scale as power of 2, 2**J, for averaging ## scattering scale of 2**6 = 64 samples J = 6 ## No. of wavelets per octave (resolve frequencies at ## a resolution of 1/16 octaves) Q = 16 # Create object to compute scattering transform scattering = Scattering1D(J, N, Q) # Compute scattering transform of our signal sample Sx = scattering(x) # Extract meta information to identify scattering coefficients meta = scattering.meta() # Zeroth-order order0 = np.where(meta['order'] == 0) # First-order order1 = np.where(meta['order'] == 1) # Second-order order2 = np.where(meta['order'] == 2) #%% # Plot original signal plt.figure(figsize=(8, 2)) plt.plot(x) plt.title('Original Signal') plt.show() # Plot zeroth-order scattering coefficient (average of # original signal at scale 2**J) plt.figure(figsize=(8,8)) plt.subplot(3, 1, 1) plt.plot(Sx[order0][0]) plt.title('Zeroth-Order Scattering') # Plot first-order scattering coefficient (arrange # along time and log-frequency) plt.subplot(3, 1, 2) plt.imshow(Sx[order1], aspect='auto') plt.title('First-order scattering') # Plot second-order scattering coefficient (arranged # along time but has two log-frequency indicies -- one # first- and one second-order frequency. Both are mixed # along the vertical axis) plt.subplot(3, 1, 3) plt.imshow(Sx[order2], aspect='auto') plt.title('Second-order scattering') plt.show() 

The print statements for the sample rate, the normalised X (data) and the number of samples are as follows:

2000000 [[-0.65671316 0.40170009] [-0.67349608 0.50152572] [-0.62685266 0.54555362] ... [-0.59829991 -0.11006975] [-0.64930253 -0.03116827] [-0.6619442 0.05557977]] 2 

There seems to be 2 samples as the main signal was split up into chunks of 2s using pydub's make_chunks and exporting them as wav format. The sample rate is 2MHz as these recordings are of RF signals stored in IQ WAV files.

However, the problem here is that I am getting the following error, from which I read seems to potentially be an issue with my J value (averaging scale):

Traceback (most recent call last): File "analyse.py", line 38, in scattering = Scattering1D(J, T, Q) File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\frontend\numpy_frontend.py", line 19, in init ScatteringBase1D.build(self) File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\frontend\base_frontend.py", line 55, in build min_to_pad = compute_minimum_support_to_pad( File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\utils.py", line 125, in compute_minimum_support_to_pad _, _, _, t_max_phi = scattering_filter_factory( File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\filter_bank.py", line 676, in scattering_filter_factory psi_f[0] = morlet_1d( File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\filter_bank.py", line 135, in morlet_1d morlet_f *= get_normalizing_factor(morlet_f, normalize=normalize) File "C:\Users\xwb18152\AppData\Roaming\Python\Python38\site-packages\kymatio\scattering1d\filter_bank.py", line 157, in get_normalizing_factor raise ValueError('Zero division error is very likely to occur, ' + ValueError: Zero division error is very likely to occur, aborting computations now.

Any help would be appreciated to understand what's going on!

EDIT: I can get to "the next step" if I use Q=1,J=1, however I get the following warning:

warnings.warn('Signal support is too small to avoid border effects'

And when trying to plot I get the error:

File "analyse.py", line 100, in <module> plt.imshow(Sx[order1], aspect='auto') [....] raise TypeError("Invalid shape {} for image data" TypeError: Invalid shape (2, 3, 1) for image data 
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  • $\begingroup$ Updated the OP with some recent attempts! $\endgroup$ Commented Mar 14, 2022 at 12:22

1 Answer 1

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Latest release is incomplete. Use dev

pip install git+https://github.com/kymatio/kymatio.git@dev 

or latest stable branch with all functionality

pip install git+https://github.com/kymatio/kymatio.git@refs/pull/674/head 

And when trying to plot I get the error:

is due to

There seems to be 2 samples as the main signal was split up

so an option is to iterate over the batch axis (0) and plot one by one.

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  • $\begingroup$ I used the second option (all functionality latest stable) and running the code gives the error AssertionError: must have at least 3 filters in filterbank (got 1) $\endgroup$ Commented Mar 14, 2022 at 13:44
  • $\begingroup$ Increasing Q to 3 gives the error: ValueError: max() arg is an empty sequence $\endgroup$ Commented Mar 14, 2022 at 13:47
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    $\begingroup$ @rshah I do not reproduce your errors. Running your code gave different errors, so I edited the working version into your question. Data loads batches into axis 1, but must be axis 0 as mentioned (also in docs). $\endgroup$ Commented Mar 14, 2022 at 16:21
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    $\begingroup$ @rshah That's right. And, they're here in help(Scattering1D). Unfortunately there aren't built-in visuals (or examples) for properly visualizing the second order; the true structure is shown here under "CWT, second order". $\endgroup$ Commented Mar 15, 2022 at 14:27
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    $\begingroup$ @rshah That's expanding the scope of the question, but briefly, order0 and order1 are fully proper, order2 is "unrolled". $\endgroup$ Commented Mar 15, 2022 at 14:38

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