It's a 250 volts source connected to 5-j10 impedance, the dependent source has a value of Vdelta/5 where Vdelta is the voltage across the j5 impedance.


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5 - 1\$\begingroup\$ Edit to show the image. \$\endgroup\$Solar Mike– Solar Mike2025-04-09 08:08:32 +00:00Commented Apr 9 at 8:08
- \$\begingroup\$ Yep I did, my bad \$\endgroup\$Jaskaran Singh– Jaskaran Singh2025-04-09 08:09:33 +00:00Commented Apr 9 at 8:09
- 1\$\begingroup\$ Welcome! Please show your attempted solution. \$\endgroup\$winny– winny2025-04-09 08:41:51 +00:00Commented Apr 9 at 8:41
- \$\begingroup\$ Okay I'll edit and add both mine and my professors solution \$\endgroup\$Jaskaran Singh– Jaskaran Singh2025-04-09 08:49:02 +00:00Commented Apr 9 at 8:49
- \$\begingroup\$ When i divide Vt with It I don't get the Zth he got \$\endgroup\$Jaskaran Singh– Jaskaran Singh2025-04-09 08:55:02 +00:00Commented Apr 9 at 8:55
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