-1
\$\begingroup\$

I am simulating a 2 by 2 patch antenna array with Wilkson power splitter.

enter image description here

enter image description here

This power splitter require 100 ohm resistor. I use 0603 for this SMD resistor.

enter image description here

Here is my EM simulation s-paramter plot in ADS for this 2 by 2 patch antenna layout.

My question is, does this EM simulation consider 100 ohm resistor here for this S-parameter result? If not , how can I add this resistor for EM sim in ADS?

enter image description here

3D Main lobe plot at 5.4975GHz.

enter image description here

\$\endgroup\$
1
  • \$\begingroup\$ Why not remove the resistor and see what happens. This is called testing an idea. \$\endgroup\$ Commented May 27 at 23:31

2 Answers 2

Reset to default
1
\$\begingroup\$

The simulation considers the resistor if you put it in the simulation. The easiest way to do that is to insert a section of line with material chosen to provide the desired resistance between the ends.

\$\endgroup\$
2
  • \$\begingroup\$ Do you mean I should model something like thin film resistor myself? What material do you recommend? \$\endgroup\$ Commented May 27 at 23:00
  • \$\begingroup\$ Suppose you build a section of line joining the two ends of the resistor. In the simulator I use I can change the material of that section. I could pick nichrome and adjust the resistance by changing the thickness. Or I could keep the thickness the same and define a custom material with higher resistivity. R = rho*length/area. \$\endgroup\$ Commented May 28 at 5:22
1
\$\begingroup\$

First, I have personally never used ADS and my experience is around AWR.

My question is, does this EM simulation consider 100 ohm resistor here for this S-parameter result?

From what I can gather from the images, no, the resistor is not included. Remember, for Wilkinson power dividers, the resistor is only there for isolation and output match. If your antennas are well matched, there shouldn't be much reflection so the resistor isn't necessarily doing anything.

If not , how can I add this resistor for EM sim in ADS?

Again, I'm not an expert in ADS. However, in AWR, there are a couple ways to approach this.

  1. Draw 2 ports where the resistor would go. The resistance is then added in post-processing. AWR does this automatically.
  2. Add material where the resistor would be to match the resistance (as proposed by another answer). This method is usually not preferred because it requires some fine tuning to get the right resistance.
\$\endgroup\$
2
  • \$\begingroup\$ Do you mean resistor it's is only for S(3,2) and S(2,3}? \$\endgroup\$ Commented May 27 at 23:02
  • \$\begingroup\$ @kile S22, S33, S23, and S32. \$\endgroup\$ Commented May 27 at 23:34

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.