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Ok so I've been working on this problem for a while now. I've been given

mux(\$p_{11}, p_{10}, p_{01}, p_{00}, x_1, x_0) = p_{x_1x_0}.\$

I found the boolean formula to be:

\$(!(x_1x_0))p_{11} + ((!x_1)x_0)P_{10} + (x_1(!x_0))p_{01} + (x_1x_0)p_{00}. \$

My question is what would the circuit that computes mux look like using only and, or, and not gates.

Thanks in advance!

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  • \$\begingroup\$ The first term in your Sum-of-products is incorrect. \$\endgroup\$ Commented Oct 9, 2013 at 18:16
  • \$\begingroup\$ Really? What would it be? \$\endgroup\$ Commented Oct 9, 2013 at 18:18
  • \$\begingroup\$ !(ab) = !a b + a !b + !a !b, so your first term is actually 3 product terms. \$\endgroup\$ Commented Oct 9, 2013 at 18:33

1 Answer 1

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It would have complement generators for x0 and x1, 3-input ands with the appropriate inputs, and a 4-input or at the end.

This should get you started:

schematic

simulate this circuit – Schematic created using CircuitLab

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