So we have this mod-16 counter with certain inputs and outputs:

We are with 2 sets of this counter supposed to realize a Mod-10 counter and Mod-2 counter. I think I know how to do that. The RCO (Ripple Carry Output) output looks like this: $$RCO = q_d \wedge q_c \wedge q_b \wedge q_a \wedge T$$

So when the counter reaches fifteen and is about to go back to 0 RCO turns 1.

If we let the counters input be:

$$(1, \overline{RCO}, 1, 1, d, c, b, a)$$

We can see that we will count up to 15 and then load the number dcba (F in decimal) When qd, qc, qb, qa = 1111 and T = 1, RCO = 1. We invert RCO to 0. Load will then invert it back to 1 and load the input number. So if we want a Mod-X counter we let F be:

$$F = 16 - X$$

So for a Mod-10 counter F in decimal is 16 - 10 = 6. As dcba = 0110. So we will count 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 6, 7, 8...

For a Mod-2 counter F in decimal is 16 - 2 = 14. As dcba = 1110. So we will count 14, 15, 14, 15...

Now we are given this task:

"Realize a Mod-10 counter and a Mod-2 counter. Presume that the counters are clocked with 2Hz. How shall they be connected in order to yield 2 outputs with the frequencies 1 Hz and 0.1 Hz. The circuit should be synchronous, i.e both counters should be using the same clock.

I'm trying and struggling to figure out how one can delay the outputs in this way. We want the Mod-10 counter to give output this many times $$2Hz \times \frac {1}{2}$$ and the Mod-2 counter $$2Hz \times \frac {1}{20}$$

So the question remains. How do I delay these signals in this particular way? As you can see below we have standard gates at our disposal but also 6 D-elements. Can they be used in any way?

For context, this is the circuit board we have available: