So we have this mod-16 counter with certain inputs and outputs:
We are with 2 sets of this counter supposed to realize a Mod-10 counter and Mod-2 counter. I think I know how to do that. The RCO (Ripple Carry Output) output looks like this: $$RCO = q_d \wedge q_c \wedge q_b \wedge q_a \wedge T$$
So when the counter reaches fifteen and is about to go back to 0 RCO turns 1.
If we let the counters input be:
$$(1, \overline{RCO}, 1, 1, d, c, b, a)$$
We can see that we will count up to 15 and then load the number dcba (F in decimal) When qd, qc, qb, qa = 1111 and T = 1, RCO = 1. We invert RCO to 0. Load will then invert it back to 1 and load the input number. So if we want a Mod-X counter we let F be:
$$F = 16 - X$$
So for a Mod-10 counter F in decimal is 16 - 10 = 6. As dcba = 0110. So we will count 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 6, 7, 8...
For a Mod-2 counter F in decimal is 16 - 2 = 14. As dcba = 1110. So we will count 14, 15, 14, 15...
Now we are given this task:
"Realize a Mod-10 counter and a Mod-2 counter. Assume the counters are clocked with the 2Hz clock. How should they be connected to get two output signals with the frequencies 1 and 0.1 Hz respectively? Note: The circuit should be synchronous, i.e using the same clock.
I'm trying and struggling to figure out how one can delay the outputs in this way. We want the Mod-10 counter to have this frequency $$2Hz \times \frac {1}{2} = 1 Hz$$ and the Mod-2 counter $$2Hz \times \frac {1}{20} = 0.1 Hz$$
So the question remains. How do I delay these signals in this particular way? As you can see below we have standard gates at our disposal but also 6 D-elements. Can they be used in any way?
For context, this is the circuit board we have available:
