Linear Algebra and the C Language/a08f

Install and compile this file in your working directory.

/* ------------------------------------ */ /* Save as : c00b.c */ /* ------------------------------------ */ #include "v_a.h" /* ------------------------------------ */ int main(void) { int n = 1; double x1 = +0.66666667; double x2 = +0.83333333; double x3 = +0.66666667; double x4 = +1.00000000;    do{   clrscrn();  printf(" Continue until integers appear : \n\n\n");    printf(" n = %d -> n*x1 = %0.4f \n",n, n*x1);  printf(" n = %d -> n*x2 = %0.4f \n",n, n*x2);  printf(" n = %d -> n*x3 = %0.4f \n",n, n*x3);   printf(" n = %d -> n*x4 = %0.4f \n",n, n*x4);     n++;    }while(stop_w());  return 0; } /* ------------------------------------ */ /* ------------------------------------ */ 

• With n = 6

n = 6 -> n*x1 = 4.0000 n = 6 -> n*x2 = 5.0000 n = 6 -> n*x3 = 4.0000 n = 6 -> n*x4 = 6.0000 

This gives us the coefficients of the equation:

$\mathrm {x_{1}NH_{3}+x_{2}O_{2}\longrightarrow x_{3}NO+x_{4}H_{2}O}$

“Simply replace x1, x2,... with their numerical values:

$\mathrm {4NH_{3}+5O_{2}\longrightarrow 4NO+6H_{2}O}$

Exemple de sortie écran : 

 ---------------------  Continue until integers appear :   n = 1 -> n*x1 = 0.6667   n = 1 -> n*x2 = 0.8333   n = 1 -> n*x3 = 0.6667   n = 1 -> n*x4 = 1.0000   Press return to continue  Press X return to stop   Continue until integers appear :   n = 2 -> n*x1 = 1.3333   n = 2 -> n*x2 = 1.6667   n = 2 -> n*x3 = 1.3333   n = 2 -> n*x4 = 2.0000   Press return to continue  Press X return to stop   Continue until integers appear :   n = 3 -> n*x1 = 2.0000   n = 3 -> n*x2 = 2.5000   n = 3 -> n*x3 = 2.0000   n = 3 -> n*x4 = 3.0000   Press return to continue  Press X return to stop   Continue until integers appear :   n = 4 -> n*x1 = 2.6667   n = 4 -> n*x2 = 3.3333   n = 4 -> n*x3 = 2.6667   n = 4 -> n*x4 = 4.0000   Press return to continue  Press X return to stop   Continue until integers appear :   n = 5 -> n*x1 = 3.3333   n = 5 -> n*x2 = 4.1667   n = 5 -> n*x3 = 3.3333   n = 5 -> n*x4 = 5.0000   Press return to continue  Press X return to stop   Continue until integers appear :   n = 6 -> n*x1 = 4.0000   n = 6 -> n*x2 = 5.0000   n = 6 -> n*x3 = 4.0000   n = 6 -> n*x4 = 6.0000   Press return to continue  Press X return to stop