Check for equality of two arrays #3
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anantkaushik requested changes Jan 26, 2020
Comment on lines 39 to 52
| def equal(arr1, arr2): | ||
| res = 0 | ||
| for i in range(len(arr1)): | ||
| res ^= arr1[i] | ||
| res ^= arr2[i] | ||
| return 0 if res else 1 | ||
| | ||
| t = int(input()) | ||
| while t > 0: | ||
| n = int(input()) | ||
| arr1 = list(map(int, input().split())) | ||
| arr2 = list(map(int, input().split())) | ||
| print(equal(arr1, arr2)) | ||
| t -= 1 |
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what if a is [1,2,1] and b is [3,2,3]
anantkaushik requested changes Jan 27, 2020
Comment on lines 39 to 44
| def equal(arr1, arr2): | ||
| res1 = res2 = 0 | ||
| for i in range(len(arr1)): | ||
| res1 ^= arr1[i] | ||
| res2 ^= arr2[i] | ||
| return 1 if res1 == res2 else 0 |
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What if a = [1,2,2,1] and b = [3,3,4,4]
anantkaushik requested changes Jan 27, 2020
Comment on lines 42 to 43
| res1 ^= arr1[i] | ||
| res2 ^= arr2[i] |
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Do we really need two variables for this?
anantkaushik approved these changes Jan 28, 2020
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Check for most optimal solution