Timeline for Show that the substitution $t=\tan\theta$ transforms the integral ${\int}\frac{d\theta}{9\cos^2\theta+\sin^2\theta}$, into ${\int}\frac{dt}{9+t^2}$
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 3, 2021 at 22:55 | answer | added | A-Level Student | timeline score: 0 | |
| Nov 16, 2018 at 1:00 | comment | added | Robert Howard | @Waffle Thanks! | |
| Nov 15, 2018 at 19:55 | answer | added | Waffle | timeline score: 2 | |
| Nov 15, 2018 at 5:14 | comment | added | Robert Howard | @Waffle Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? | |
| Apr 8, 2015 at 13:06 | history | edited | N. F. Taussig | CC BY-SA 3.0 | corrected spelling |
| Apr 8, 2015 at 11:57 | history | edited | kennytm | CC BY-SA 3.0 | sin → \sin, etc. |
| Apr 8, 2015 at 11:56 | comment | added | Waffle | $sec^2\theta=\frac{1}{cos^2\theta} \implies cos^2\theta sec^2\theta = 1$ | |
| Apr 8, 2015 at 11:56 | history | edited | kennytm | CC BY-SA 3.0 | sin → \sin, etc. |
| Apr 8, 2015 at 11:49 | history | edited | Thomas Winkworth | CC BY-SA 3.0 | added 25 characters in body |
| Apr 8, 2015 at 11:49 | comment | added | lab bhattacharjee | Define $\cos\theta,\sec\theta$ | |
| Apr 8, 2015 at 11:47 | history | asked | Thomas Winkworth | CC BY-SA 3.0 |