Timeline for Borel sigma algebra of the range of an injective measurable function consists of all images of the Borel sets of the domain
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Nov 12 at 10:05 | vote | accept | guest1 | ||
| Nov 11 at 23:42 | answer | added | Ramiro | timeline score: 2 | |
| Nov 11 at 12:43 | history | edited | guest1 | CC BY-SA 4.0 | added 295 characters in body |
| Nov 11 at 12:17 | history | reopened | guest1 amWhy Dean Miller Another User Dermot Craddock | ||
| Nov 11 at 10:49 | history | edited | Dean Miller | CC BY-SA 4.0 | Fixed some further typos. |
| Nov 11 at 10:42 | history | edited | guest1 | CC BY-SA 4.0 | I have made the question more precise and corrected some mistakes. |
| Nov 11 at 9:01 | review | Reopen votes | |||
| Nov 11 at 12:17 | |||||
| Nov 11 at 9:00 | history | left closed in review | Harish Chandra Rajpoot José Carlos Santos Another User | Original close reason(s) were not resolved | |
| Nov 11 at 8:19 | comment | added | guest1 | @KaviRamaMurthy Thanks for your comments. Yes I did indeed forgot to mention that the spaces need to be Polish. Sorry for this inconvenience | |
| S Nov 11 at 8:18 | review | Reopen votes | |||
| Nov 11 at 9:00 | |||||
| S Nov 11 at 8:18 | history | edited | guest1 | CC BY-SA 4.0 | added 71 characters in body Added to review |
| Nov 11 at 5:01 | history | closed | Kavi Rama Murthy Harish Chandra Rajpoot Leucippus Bowei Tang Afntu | Not suitable for this site | |
| Nov 10 at 23:20 | review | Close votes | |||
| Nov 11 at 5:01 | |||||
| Nov 10 at 23:12 | answer | added | Ramiro | timeline score: 2 | |
| Nov 10 at 22:56 | comment | added | Kavi Rama Murthy | Consider the identity map from $\mathbb R$ with power set to $\mathbb R$ with $\{\emptyset, \mathbb R\}$. This is injective and measurable, but does not map measurable sets to measurable sets. Such things have been pointed out to you many times in the past but you keep ignoring them. I am downvoting your question. | |
| Nov 10 at 22:43 | comment | added | Kavi Rama Murthy | According to which theorem $A\in\mathcal{B}(X)$, implies that $f(A)\in\mathcal{B}(Y)$ if $f$ is measurable and injective ? I don't think this is true for general measurable spaces. | |
| Nov 10 at 14:03 | history | asked | guest1 | CC BY-SA 4.0 |