0
$\begingroup$

For all strictly monotonic increasing function $f:[0, \infty) \rightarrow [0,\infty)$ such that $f(0)=0$ and $lim_{x\rightarrow \infty} f(x)=\infty$, I would like to know if there always exists another strictly monotonic increasing function $f_2:[0, \infty) \rightarrow [0,\infty)$ with the same properties as $f$ such that $f(x_1)+f(x_2)\geq f_2(x_1+x_2)$ for all $x_1$, $x_2\geq0$.

I try to find a funtion from $f$, but I couldn't do it.

Thank you.

$\endgroup$

1 Answer 1

0
$\begingroup$

Let $f_2(x):=f(\frac{x}{2})$. For $x_1,x_2 \ge 0$, we can assume that $x_2 \le x_1$. Then we have $\frac{x_1+x_2}{2} \le x_1$, hence

$f_2(x_1+x_2)=f(\frac{x_1+x_2}{2}) \le f(x_1) \le f(x_1)+f(x_2)$

Fred

$\endgroup$
1
  • $\begingroup$ This is what I had in mind, but I got confused. Thank you. $\endgroup$ Commented Oct 25, 2016 at 8:23

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.