1
$\begingroup$

I've only really worked with real-valued random variables. But suppose $X$ is a random variable taking values in $\mathbb{S}^{n-1}$. What does it mean for $X$ to be uniformly distributed?

The distribution is just $P(X \in A)$ for $A \subset \mathbb{S}^{n-1}$. What does it mean for this to be a uniform distribution? I have a hunch that this means it behaves like the spherical measure $\sigma$ on $\mathbb{S}^{n-1}$. But I do not know the formal definition so I'd appreciate someone explaining that to me.

A related question is whether there is only one such uniform measure on the sphere, up to a constant multiple. It feels rather like the question of Haar measure on a locally compact Abelian group, but that's only for translation invariance. Here we're really talking about rotation invariance. That, after all, is what $\sigma$ is all about. Is there such a uniqueness statement for rotationally invariant measures on the sphere, and could one prove that using the uniqueness of Haar measure?

$\endgroup$

1 Answer 1

3
$\begingroup$

Uniform distribution on the sphere means the natural rotationally-invariant probability measure on the sphere. The sphere $S^{n-1}$ can be considered as the homogeneous manifold $SO(n)/SO(n-1)$, and Haar measure on $SO(n)$ then induces this measure on $S^{n-1}$.

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.