1
$\begingroup$

For context, I'm a college student studying Integral Calculus for the first time.

When I solve $\int \:\:\frac{secx\cdot \:cos\left(2x\right)}{sinx+secx}dx$ by hand, I get $\ln\left(\sin\left(2x\right)+2\right)+c$. When I put the integral into Wolfram Alpha, I get $\log\left(\sin\left(2x\right)+2\right)+c$. When I evaluate a definite integral with the bounds of 0 to 5, I get the same answer by hand and via Wolfram Alpha, even though Wolfram Alpha gives me a different anti derivative.

Thoughts? Thanks for the assistance!

$\endgroup$
3
  • 4
    $\begingroup$ Sorry, where is the difference in the antiderivatives? Wolfram|Alpha will use log to denote the natural logarithm, so it looks like the antiderivatives are the same. $\endgroup$ Commented Oct 16, 2020 at 1:57
  • $\begingroup$ Use this too:integral-calculator.com I found this pretty helpful when I was doing Calc 2. It's not perfect but it may help. $\endgroup$ Commented Oct 16, 2020 at 2:22
  • 1
    $\begingroup$ @E__. May be not perfect but it gave me several times solutions i was not obtainable by WA. $\endgroup$ Commented Oct 16, 2020 at 3:59

1 Answer 1

Reset to default
1
$\begingroup$

In this case, Wolfram Alpha is using log with no base attached to it to mean the natural logarithm. These are the same antiderivatives.

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.