4
$\begingroup$

Is there a way to solve the following for $y(t)$:

$$ y'(t)a(t)+y(t)b(t) + c(t)X_t=0 $$

where, $X_t$ is a stochastic process satisfying $dX_t=X_t(\mu(t)dt+\sigma(t)dW_t)$? Here $W_t$ is a Brownian Motion.

What is the general concept that deals with such problems? Are there some assumptions that must be satisfied for it to be solvable?

$\endgroup$
1

1 Answer 1

6
$\begingroup$

Since the stochastic process $X_t$ appears only in the source term, you can solve this differential equation with respect to $y(t)$ as usual, hence $$ y(t) = y(0)e^{F(t)} - \int_0^t \frac{c(s)}{a(s)} X_se^{F(t)-F(s)} \mathrm{d}s, $$ where $F(t) = -\displaystyle\int_0^t \frac{b(\tau)}{a(\tau)} \mathrm{d}\tau$.

$\endgroup$
1
  • $\begingroup$ furthermore, if you can sample different implementations of the stochastic input, and thus get sampled solution for the distribution of input noise $\endgroup$ Commented yesterday

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.